Question

Someone please answer this percent yield question

Answer 1

Answer:

388.94 g N₂

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Chemistry

Atomic Structure

• Reading a Periodic Table
• Using Stoichiometry

Explanation:

Step 1: Define

[RxN]   4HCl (g) + 6NO (g) → 5N₂ (g) + 6H₂O (g)

[Given]   404.87 g HCl

Step 2: Identify Conversions

[RxN]   4 mol HCl = 5 mol N₂

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of N₂ - 2(14.01) = 28.02 g/mol

Step 3: Stoichiometry

$404.87 \ g \ HCl(\frac{1 \ mol \ HCl}{36.46 \ g \ HCl} )(\frac{5 \ mol \ N_2}{4 \ mol \ HCl} )(\frac{28.02 \ g \ N_2}{1 \ mol \ N_2} )$ = 388.935 g N₂

Step 4: Check

We are given 5 sig figs. Follow sig fig rules and round.

388.935 g N₂ ≈ 388.94 g N₂