Answer:
218.09g
Explanation:
the formula for density is mass/volume
you have volume so rlly what you have is 19.3g/cm3=m/11.3cm3
so mass equals density x volume
and 19.3 x 11.3 = 218.09
At the very least, an oxoacid must 1) be an acid and 2) contain oxygen.
Ba(OH)2 (barium hydroxide) is a strong base. HCN, HF, and hydrochloric acid (HCl) don't contain oxygen.
Nitrous acid (HNO2) is an acid, and it contains oxygen. And the acidic hydrogen is bonded to an oxygen. Thus, nitrous acid qualifies as an oxoacid.
I don't know if H2PO4 is a typo; if not, then it would properly be written as H2PO4⁻ since it's the first deprotonation product of phosphoric acid, H3PO4. In any case, H2PO4⁻ is still acidic, albeit weakly, and its acidic hydrogens are bonded to the oxygen atoms. Thus, "H2PO4" would qualify as an oxoacid (for that matter, H3PO4 would also be an oxoacid).
Chloric acid (HClO3) is an acid, and it contains oxygen; its acidic hydrogen is bonded to an oxygen atom. Thus, chloric acid qualifies as an oxoacid.
Answer:
3.4 × 10
^−
4
Explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the
10
. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
W = F * s
W = 100 * 10
W = 1000 J
In short, Your Answer would be 1000 Joules
Hope this helps!
Answer:
45.3°C
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 82KPa
Initial temperature (T1) = 26°C
Final pressure (P2) = 87.3KPa.
Final temperature (T2) =.?
Step 2:
Conversion of celsius temperature to Kelvin temperature.
This is illustrated below:
T(K) = T(°C) + 273
Initial temperature (T1) = 26°C
Initial temperature (T1) = 26°C + 273 = 299K.
Step 3:
Determination of the new temperature of the gas. This can be obtained as follow:
P1/T1 = P2/T2
82/299 = 87.3/T2
Cross multiply to express in linear form
82 x T2 = 299 x 87.3
Divide both side by 82
T2 = (299 x 87.3) /82
T2 = 318.3K
Step 4:
Conversion of 318.3K to celsius temperature. This is illustrated below:
T(°C) = T(K) – 273
T(K) = 318.3K
T(°C) = 318.3 – 273
T(°C) = 45.3°C.
Therefore, the new temperature of the gas in th tire is 45.3°C
