Question

Na3po4 dissolves in water to produce an electrolytic solution. what is the osmolarity of a 2. 0 × 10-3 m na3po4 solution?

Answer 1

When Na3po4 dissolves in water to produce an electrolytic solution. The osmolarity of a 2. 0 × 10-3 m Na3po4 solution is 0.008osmol/L.

Osmolarity is defined as the number of osmoles of solute particles per unit volume of the solution.

In other words osmolarity is the multiple if molarity

Osmolarity = i× molarity

Here i represents the van't Hoff factor,

$Na_{3}PO_{4}$ ⇒ $3Na^{+} + PO_{4} ^{-}$

3  Moles of $Na_{} ^{+}$ + 1 mole $PO_{4} ^{-}$ = 4

The number of moles of particles of solute produced in solution are actually called osmoles.

As a result, the van't Hoff factor will be equal to

i=4 Moles ions produced (osmoles) 1mole $Na_{3} PO_{4}$ .dissolved =4

Since we know that,

$Na_{3} PO_{4}$ = $2.0 * 10^{-3} M$

Osmolarity =

$4*2.0*10^{-3} M$ = $8.0 * 10^{-3} osmol L -10s$

Thus, the Osmolarity of given solution is 0.008 osmol/L.

learn more about Osmolarity:

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