They also have a specialized non-lignified tissue (the phloem) to conduct products of photosynthesis. Vascular plants include the clubmosses<span>, </span>horsetails<span>, </span>ferns,gymnosperms<span> (including </span>conifers<span>) and </span>angiosperms<span> (flowering plants). Scientific names for the group include </span>Tracheophyta<span> and </span>Tracheobionta<span>.</span>
Answer:
The answer to your question is: kc = 6.48
Explanation:
Data
Given Molecular weight
CaO = 44.6 g 56 g
CO₂ = 26 g 44 g
CaCO₃ = 42.3 g 100 g
Find moles
CaO 56 g ---------------- 1 mol
44.6 g -------------- x
x = (44.6 x 1) / 56 = 0.8 mol
CO₂ 44 g ----------------- 1 mol
26 g ---------------- x
x = (26 x 1 ) / 44 = 0.6 moles
CaCO₃ 100 g --------------- 1 mol
42.3g -------------- x
x = (42.3 x 1) / 100 = 0.423 moles
Concentrations
CaO = 0.8 / 6.5 = 0.12 M
CO₂ = 0.6 / 6.5 = 0.09 M
CaCO₃ = 0.423 / 6.5 = 0.07 M
Equilibrium constant =
Kc = [0.07] / [[0.12][0.09]
Kc = 0.07 / 0.0108
kc = 6.48
What is the theoretical yield of aluminum oxide if 2.40 mol of aluminum metal is exposed to 2.10 mol of oxygen?<span><span>Ask for details </span><span>Follow </span>Report</span><span> by <span>Sapperd2248 </span><span>1 minute ago
1879</span></span>
We are given with the ionic equation
<span>Li+(aq) + OH−(aq) + H+(aq) + Cl−(aq) → Li+(aq) + Cl−(aq) + H2O(l)
First, let us make sure that the equation is balanced. By inspection, the species on the left is balanced with the species on the right.
Next, we must identify any spectator ions. These are ions which are present in both the reactant and product side. The spectator ions are
Li+ (aq)</span>
Cl−(aq)
Cancel out the spectator ions resulting in the net ionic equation.
OH−(aq) + H+(aq) → H2O(l) <span />