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Iteru [2.4K]
3 years ago
7

Rhia is using the above equation to investigate the carbon footprint, ccc, in kilograms of carbon dioxide (co_2)(co 2 ​ )left pa

renthesis, c, o, start subscript, 2, end subscript, right parenthesis emissions, for her morning commute, during which sss miles are by subway and bbb miles are by bus. how many kilograms of co_2co 2 ​ c, o, start subscript, 2, end subscript per mile does the bus portion contribute to rhia's carbon footprint?
Chemistry
1 answer:
Drupady [299]3 years ago
8 0

Answer: -

0.2 Kg

Explanation: -

The equation used by Rhia for the carbon footprint measurement is

C = 0.2 B + 0.1 S

where S miles are by subway, B miles by bus and C is Kg of carbon dioxide.

From the equation we see the coefficient of B is 0.2.

Thus 0.2 Kg of carbon dioxide per mile the bus portion contributes to Rhia's carbon footprint.

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A physical property is any property of matter or energy that can be measured. It is an attribute of matter that can be observed or perceived.

Common Physical Properties
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Absorption (physical) - Absorption between two forms of matter
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Area - Amount of a two dimensional surface in a plane
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Capacitance - Ability of an object to store an electrical charge
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6 0
3 years ago
Read 2 more answers
Name the following alkyne: CH3CH₂C = CCH₂CH₂CH3
liubo4ka [24]

The given alkyne is Option A 3-heptyne

<h3>What is an Alkyne ?</h3>

The hydrocarbon having at least one C-C triple bond is called an Alkyne.

It has the general formula of   \rm C_n H_{2n+2} .

In the question it is being mentioned that it is an alkyne so there will be a triple bond and not a double bond.

It has been asked in the question that

CH3CH₂C ≡  CCH₂CH₂CH3 is which alkyne from the given option.

The counting of the Carbon chain is done from the left side and the Triple bond is at the 3rd Carbon , so 3-heptyne .

To know more about Alkyne

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<h3 />

6 0
2 years ago
Unlabeled atoms joined to carbon atoms, which are not directly part of a ring structure, are assumed to be oxygen atoms.
N76 [4]
The statement above is FALSE.
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3 0
3 years ago
A solution contains 45 grams of nitrogen gas and 40 grams of argon. What is the mole fraction of argon in this solution?
Katarina [22]
 <span>0.38 

You first calculate the total moles by dividing the grams by molecular weight: 
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Then you divide the moles of Ar by the total number of moles: 
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8 0
4 years ago
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Ghella [55]

Decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

As we know that rate of reaction is directly proportional to the concentration of the reactant.

If we increase the concentration of H2 then the rate of reaction increases. So, we keep it constant. Therefore this option is wrong.

By removing the H₂O from the reaction vessel as it almost make no change in the reaction. This can be pursuited the reaction in which product again converted into product.

By increasing the temperature we increases the rate of reaction and equilibrium shift in the forward direction.

Thus, we concluded that by decreasing the temperature in the reaction vessel keep this reaction from shifting to form more of the product.

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5 0
1 year ago
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