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2 years ago

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Mathematics

2 answers:

larisa [96]2 years ago

5 0

The ratio can be simplified from 3:18 to 1:6.

deff fn [24]2 years ago

3 0

Answer:

1 to 6

Step-by-step explanation:

the ratio is found by dividing 18 by 3 which is 6.

basically, one squirrel per 6 acorns

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Would you like some points? Its 20

bogdanovich [222]

Answer:

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2 years ago

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If f(x) and f⁻¹(x) are inverse functions of each other and f(x)=2x+5, what is f⁻¹(8)?

dexar [7]

Answer:

3/2.

Step-by-step explanation:

f(x)=2x+5 Finding the inverse:

y = 2x + 5

2x = y - 5

x = (y - 5)/2

So the inverse f-1(x) = (x - 5)/2

and f-1(8) = (8-5)/2

= 3/2.

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3 years ago

7-70. Use your preferred method to solve

kirill [66]

Answer:

You would want to divide 6 by 2, getting x=3.

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2 years ago

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Solve the following equation. Please show all work x/x-2+x-1/x+1=-1

Ainat [17]

Im not sure but i think its 1.22474487

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4 0

3 years ago

In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

8 0

3 years ago