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Alex787 [66]
3 years ago
6

Two numbers have an HCF of 84 and an LCM of 4620. Both numbers are larger than the

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

420 & 924

Step-by-step explanation:

hope it helps!

...

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Solve algebraically the simultaneous equations
Bess [88]

Answer:waffle

Step-by-step explanation:

Basically ill tell you the answer if it says it helped you

8 0
2 years ago
What is the equation of the line in point slope form given a slope of -3 and a point of (-2,-5)?​
Lelu [443]

Answer:

y = -3x - 11

Step-by-step explanation:

Use the given slope and point in the point-slope equation. Solving this will give us the y-intercept equation.

Point-slope formula: y - y = m(x - x)

Plug in the slope and point

y - (-5) = -3(x - (-2))

Subtracting negatives will make them positive. Multiply out the -3 to what is in the parentheses.

y + 5 = -3x - 6

Subtract the 5 from both sides

y = -3x - 11

The equation of the line is y = -3x - 11

7 0
3 years ago
For what values of θ on the polar curve r=θ, with 0≤θ≤2π , are the tangent lines horizontal? Vertical?
Bond [772]
Given that r=\theta, then r'=1

The slope of a tangent line in the polar coordinate is given by:

m= \frac{r'\sin\theta+r\cos\theta}{r'\cos\theta-r\sin\theta}

Thus, we have:

m= \frac{\sin\theta+\theta\cos\theta}{\cos\theta-\theta\sin\theta}



Part A:

For horizontal tangent lines, m = 0.

Thus, we have:

\sin\theta+\theta\cos\theta=0 \\  \\ \theta\cos\theta=-\sin\theta \\  \\ \theta=- \frac{\sin\theta}{\cos\theta} =-\tan\theta

Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are horizontal are:

</span><span>θ = 0

</span>θ = <span>2.02875783811043
</span>
θ = <span>4.91318043943488



Part B:

For vertical tangent lines, \frac{1}{m} =0

Thus, we have:

\cos\theta-\theta\sin\theta=0 \\  \\ \Rightarrow\theta\sin\theta=\cos\theta \\  \\ \Rightarrow\theta= \frac{\cos\theta}{\sin\theta} =\sec\theta

</span>Therefore, the <span>values of θ on the polar curve r = θ, with 0 ≤ θ ≤ 2π, such that the tangent lines are vertical are:

</span>θ = <span>4.91718592528713</span>
3 0
3 years ago
2.375 in expanded form
kari74 [83]

Answer:

2375^-3

Step-by-step explanation:

Move the decimal place from 2.375 to the back of the number so it should look like this, 2375.

Than move the decimal place back to its original spot and count the amount of spaces you move. Remember, if you move forward, your exponent should be negative. For example, if the problem is 6.321, you would move the decimal place to the back like this, 6321. And then move it back to where it originally was, 6.321, the amount of spaces I moved was 3 spaces and I moved forward so It would be 6.321^-3

6 0
3 years ago
3:20pm to 8:00 pm how many hour's is that
Alex
4 hours and 40 minutes
6 0
3 years ago
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