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3 years ago

PLSS HELP ME ASAP!! I WILL GIVE YOU BRAINLYEST!

Mathematics

2 answers:

babunello [35]3 years ago

6 0

the answer tho this is that the tree is 14ft

bagirrra123 [75]3 years ago

3 0

Answer:

22.5

Step-by-step explanation:

20 ft for an 8 foot shadow but since you need 1 more foot

take half of 5 (2.5) and you get 22.5

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Write an equation for the nth term of the arithmetic sequence.

tresset_1 [31]

Answer:

Step-by-step explanation:

3, 9, 15, 21, ...

9-3 = 6; 15-9 = 6; 21-15 = 6 ⇒ d = 6

first term: a = 3

difference: d = 6

so the formula:

$a_n=a+d(n-1)\\\\a_n=69+6(n-1)\\\\a_n =3+6n-6\\\\\underline{a_n=6n-3}$

and:

$a_{50}=6\cdot50-3=300-3=297$

5 0

2 years ago

A right triangle includes one angle that mesures 30 degrees. What is the measure of the third angle?

Airida [17]

The third angle is 60 degrees. A triangle has 180 degrees so 180-30-90=60

5 0

3 years ago

Read 2 more answers

2x+4y=6<br> 3x=12-6y<br> Solve by elimination

faltersainse [42]

Answer:

no solution

Step-by-step explanation:

2x + 4y = 6......reduces to x + 2y = 3

3x = 12 - 6y....reduces to x = 4 - 2y...rearranged is x + 2y = 4

so now we have :

x + 2y = 3

x + 2y = 4

ok....I dont have to go any farther to know that this has no solution because ur equations have the same slope and different y int, this means ur lines are parallel and have no solution because they never cross each others path.

5 0

3 years ago

Read 2 more answers

What is x, the distance between points A and A'? 2. 4 units 4. 8 units 13. 6 units 14. 4 units.

adelina 88 [10]

The distance between points A (3, -5) and A' (2, -3) is 2.4 units.

Given that,

The points A (3, -5) and A' (2, -3).

We have to determine,

The distance between point A and A'.

According to the question,

The distance between two points is determined by using the distance formula.

$\rm Distance \ formula = \sqrt{(x_2-x_2) ^2+ (y_2-y_2)^2$

Then,

The distance between points A (3, -5) and A' (2, -3) is,

$\rm Distance = \sqrt{(2-3) ^2+ ((-3)-(-5))^2}\\\\ Distance = \sqrt{(-1) ^2+ (2)^2}\\\\ Distance = \sqrt{1+4}\\\\Distance = \sqrt{5}\\\\Distance = 2.4 \ units$