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Stells [14]
3 years ago
11

Would you rather have infinite money but tell God you hate him and don't want anything to do with him or not take the money and

be with God.
Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

Not take the money

Step-by-step explanation:

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What is the fraction that is halfway between 1/3 and 3/2
stellarik [79]

Answer:

11/12

Explanation:

1/3 + 3/2 = 11/6

11/6 x 1/2 (average is halfway) = 11/12

5 0
3 years ago
Read 2 more answers
Mallory puts $1.00 in a jar. The following week, she puts 2 times that original amount in the jar. For each of the next six week
Burka [1]

The relationship of the ordered pair that represents Mallory savings is a nonlinear relationship.

Let x represents the number of weeks, and y represents the amount put in the jar, each week.

So, we have the following highlights for 6 weeks.

  • Week 1: (1, 1)
  • Week 2: (2,2)
  • Week 3: (3,4)
  • Week 4: (4,8)
  • Week 5: (5,16)
  • Week 6: (6,32)

The ordered pairs can then be represented as:

(x,y) = (1,1)(2,2)(3,4)(4,8)(5,16)(6,32)

As the x values increase, the y values increase too, but the y values do not increase at a constant rate.

This means that the relationship is not linear; it is an exponential relationship.

Hence, the relationship is a nonlinear relationship.

Read more about linear relationships at:

brainly.com/question/7040405

8 0
2 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
Is the product of 12 and 3/4 more or less than 12? Please explain answer
denis23 [38]
Hello!!

So the product is when numbers or variables are multiplied together. So if we have 12 * 3/4 then that equals 12/1*3/4=(12*3)/4=36/4=9

So we can see that the product of 12*3/4 is less than 12. We can see this right from the start by noticing that to be at least 12, then 12 would have to be multiplied by at minimum 1 meaning 12*1=12 anything less than 1 would result in a lesser value than 12.

Hope this helps!! Any questions please just ask!! Thank you!!!
7 0
3 years ago
Read 2 more answers
Can you please help me with this problem?
Hoochie [10]
Here you have to find which each variable is, for this you start of picking one equation,

x + 2y + 6z = 4
-3x + 2y - 2 = -4
4x + 2z = 16

depending the equation you pick you multiply that by a certain number that will give you the opposite of one of the other equations,
-1(x + 2y + 6z = 4)
= -x -2y - 6z = -4

With this you add or subtract it with the equation that has the same number or variable, or both,
In this case it will be the equation,
-3x + 2y + 6z = 4
You can use this one or the third equation since both have a positive 2y which will cancel with -2y from the new equation,
-x - 2y - 6z = -4
-3x + 2y -z = -4

= -4x -7z = -8
Now you since you just eliminated the variable (y) you now have 2 variables, and the last equation has only 2 variables, meaning now you find the answer to those to equations,

-4x -7z = -8
4x + 2z = 16

= -5z = 8
Now leave the variable by itself,
z = 8/5
Now you found the variable (z), with this just substitute on one of the equations we used to find (z) so you can find (x), after that substitute those answered to on of the original equations so you can find (y)




6 0
3 years ago
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