Answer:
Explanation:
Given data
Ex = Ey = 0
Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)
To find
The amplitude of the magnetic field component
Solution
The electric field is given by:
Ez=(4.3V/m)cos(π×10¹⁵s⁻¹)(t-x/c)
Where Em=4.3 V/m
The magnitude of magnetic field is given by:
Where Em is amplitude of electric field and c is speed of light.
Substitute the given values
So
To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,
Here,
m = Mass
V = Velocity
Replacing,
Therefore the final kinetic energy of the two car system is 72.6kJ
The rod's mass moment of inertia is 5kgm².
<h3>Moment of Inertia:</h3>The "sum of the product of mass" of each particle with the "square of its distance from the axis of rotation" is the formula for the moment of inertia.
The Parallel axis Theorem can be used to compute the moment of inertia about the end of the rod directly or to derive it from the center of mass expression. I = kg m². We can use the equation for I of a cylinder around its end if the thickness is not insignificant.
If we look at the rod we can assume that it is uniform. Therefore the linear density will remain constant and we have;
or = M / L = dm / dl
dm = (M / L) dl
Here the variable of the integration is the length (dl). The limits have changed from M to the required fraction of L.
Mass of the rod = 15 kg
Length of the rod = 2.0 m
Moment of Inertia, I =
= 5 kgm²
Therefore, the moment of inertia is 5kgm².
Learn more about moment of inertia here:
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