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brilliants [131]
3 years ago
13

Differentiate between:a. Compression and Rarefaction​

Physics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

Explanation:

Compression

The region in a medium where the distance between the vibrating molecules is minimum is compression.

This is the region with higher air pressure than the surrounding .

Rarefaction

The region in a medium where the distance between the vibrating molecules is maximum is rarefaction.

This is the region with relatively low air pressure.

hope it helps :)

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Answer:

Electric charge

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Faster

True

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positive to negative

Explanation:

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3 years ago
Why is physics an important part of history
tigry1 [53]

Answer:

History and physics are intertwined through all the revolutionary thinkers, scientists, and people who studied these ideas. For example, many historical thinkers such as Isaac Newton and Galileo Galilei not only had revolutionary ideas, but they also changed life forever as the people knew it. It shocked the people and taught them new things, and upset the church.

Explanation:

8 0
4 years ago
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A horizontal board of negligible thickness and area 2.0 m2 hangs from a spring scale that reads 80 N when a 4.0 m/s wind moves b
ki77a [65]

Answer:

Scale reading for no wind W'=60N

Explanation:

From the question we are told that

Area A= 2.0 m^2

Weight of board W=80

Velocity V=4.0m/s

Density of air \delta= 1.25 kg/m3 .

Generally the equation for pressure difference by Bernoulli equation is mathematically given by

  dP=\frac{1}{2}pv^2

  dP=10Pa

Generally force acting on the board by air is mathematically given by

F=\triangle PA

F=(10)2=>20N

Therefore

Scale reading for no wind W'

W'=W-F\\W'=80-20

W'=60N

Scale reading for no wind W'=60N

6 0
3 years ago
A point charge A of charge +4micro coloumb and another B of -1 micro coloumb are placed at a distance in air 1m apart then the d
andrew11 [14]

Answer:

Explanation:

Given that,

A point charge is placed between two charges

Q1 = 4 μC

Q2 = -1 μC

Distance between the two charges is 1m

We want to find the point when the electric field will be zero.

Electric field can be calculated using

E = kQ/r²

Let the point charge be at a distance x from the first charge Q1, then, it will be at 1 -x from the second charge.

Then, the magnitude of the electric at point x is zero.

E = kQ1 / r² + kQ2 / r²

0 = kQ1 / x²  - kQ2 / (1-x)²

kQ1 / x² = kQ2 / (1-x)²

Divide through by k

Q1 / x² = Q2 / (1-x)²

4μ / x² = 1μ / (1 - x)²

Divide through by μ

4 / x² = 1 / (1-x)²

Cross multiply

4(1-x)² = x²

4(1-2x+x²) = x²

4 - 8x + 4x² = x²

4x² - 8x + 4 - x² = 0

3x² - 8x + 4 = 0

Check attachment for solution of quadratic equation

We found that,

x = 2m or x = ⅔m

So, the electric field will be zero if placed ⅔m from point charge A, OR ⅓m from point charge B.

5 0
3 years ago
Halogens (Group 17) have<br> valence electrons and will<br> to become stable
Katena32 [7]

Answer:

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Explanation:

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