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FinnZ [79.3K]
3 years ago
8

Amir observes Wave 1 and Wave 2 crashing into each other at two different intervals. His experiments produce Wave 3 and Wave 4.

Amir records his data in a table.


What is the best statement about the data collected in Amir’s table?

Wave 3 resulted from destructive interference, and Wave 4 resulted from constructive interference.

Waves 3 and 4 resulted from constructive interference.

Waves 3 and 4 resulted from destructive interference.

Wave 3 resulted from constructive interference, and Wave 4 resulted from destructive interference.

​
Physics
2 answers:
nika2105 [10]3 years ago
7 0

Answer:

d................................................................................,...................................

Explanation:

V125BC [204]3 years ago
3 0

Answer:

D

Explanation:

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Answer:

\frac{F_e}{F_g} = 2.3 \times 10^{18}

Explanation:

The gravitational force is given by Newton's Law of Gravity:

F_g = \frac{Gm_1m_2}{r^2}

The electrostatic force is given by Coulomb's Law:

F_e = \frac{kq_1q_2}{r^2}

The ratio between these two forces is

\frac{F_e}{F_g} = \frac{\frac{kq_1q_2}{r^2}}{\frac{Gm_1m_2}{r^2}} = \frac{kq_1q_2}{Gm_1m_2} = \frac{(8.99\times 10^{-12})(1.6\times 10^{-19})(1.6 \times 10^{-19})}{(6.67\times 10^{-11})(9.1 \times 10^{-31})(1.6 \times 10^{-27})} = 2.3 \times 10^{18}

7 0
4 years ago
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Which of the following statements is an accurate description of sound transmission through various mediums? A. Gases conduct sou
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C. Sound insulators prevent sound from being transmitted better than elastic solids

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4 years ago
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How are frequency,wavelength and pitch related
nikdorinn [45]
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4 0
3 years ago
Capacitors C1 = 6.45 µF and C2 = 2.50 µF are charged as a parallel combination across a 250 V battery. The capacitors are discon
denpristay [2]

Answer:

For C1, Q =  1.6125×10⁻³ C

For C2, Q =  6.25×10⁻⁴ C

Explanation:

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From the question,

Q = CV........................ Equation 1

Where Q = Charge on the capacitor, V = Voltage across the capacitor, C = Capacitance of the capacitor.

For the first capacitor,

Q = C1V............. Equation 2

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Substitute into equation 2

Q = (6.45×10⁻⁶ )(250)

Q = 1.6125×10⁻³ C.

For the the second capacitor,

Q = C2V............. Equation 3

Given: C2 = 2.50 μF = 2.5×10⁻⁶ F, V = 250 V

Q = (2.5×10⁻⁶ )(250)

Q = 6.25×10⁻⁴ C

4 0
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