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bixtya [17]
3 years ago
12

Simplify.

) " alt="-4y^{2}(5y^4-3y^2+2) " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Vinvika [58]3 years ago
4 0
Hey there!

\left[\begin{array}{ccc}\boxed{\boxed{0-((4*(y^2))*(((5*(y^4))-3y^2)+2))}}\end{array}\right]  \\ \\ 0 -  (22y^2 * (5y^4 - 3y^2 + 2)) \\ \\ by \ factoring \    5y^4-3y^2+2, \ we \ would \ get \ the \ answer! \\ \\    \boxed{0 -  22y^2 * (5y4 - 3y^2 + 2)} \\ \\ your \ final \ answer \ would \ be....... \\ \\ \boxed{\boxed{  -22y^2 * (5y^4 - 3y^2 + 2)}} \\ \\


I hope this helps you!
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Find the vertex of the equation x2-4x+5=0
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Answer:

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Step-by-step explanation:

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</span>
3 0
3 years ago
Please help!
laila [671]
Because
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Read 2 more answers
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