The situation can be modeled by a geometric sequence with an initial term of 284. The student population will be 104% of the prior year, so the common ratio is 1.04.
Let \displaystyle PP be the student population and \displaystyle nn be the number of years after 2013. Using the explicit formula for a geometric sequence we get
{P}_{n} =284\cdot {1.04}^{n}P
n
=284⋅1.04
n
We can find the number of years since 2013 by subtracting.
\displaystyle 2020 - 2013=72020−2013=7
We are looking for the population after 7 years. We can substitute 7 for \displaystyle nn to estimate the population in 2020.
\displaystyle {P}_{7}=284\cdot {1.04}^{7}\approx 374P
7
=284⋅1.04
7
≈374
The student population will be about 374 in 2020.
Answer:
Step-by-step explanation:
we know that
The area of the figure is equal to the area of an isosceles triangle (has two equal sides) plus the area of a rectangle
step 1
Find the area of the triangle
The area of the triangle is equal to
we have
To find out the height of the triangle Apply the Pythagorean Theorem
solve for h
<em>Find the area of triangle</em>
step 2
Find the area of rectangle
The area of rectangle is equal to
we have
substitute
step 3
Find the area of the figure
Adds the areas
<u>By first equation,</u>
<u>Now, we can find the original value of y.</u>
<u>Now, we can find the original value of x.</u>
Therefore, the values of x and y are 5 and 2 respectively.
Hello!
To find the interquartile range, subtract the value of the upper quartile from the value of the lower quartile.
33 - 25 = 8
The interquartile range is 8. Hope I helped! :3
You need to use the distributive property. So you take the -9 from outside the parentheses and multiply itself by the numbers inside.
