4. Mr. Ames is dragging a box full of books from his office to his car. The box and books together have a
1 answer:
Answer:
F = 73.7 N = 74 N (rounding off)
Explanation:
In order to get the box to start moving, Mr. Ames must push it with a force equal to the frictional force acting on it. Therefore, this force can be calculated through the following formula:
where,
μ = coefficient of friction = 0.55
R = Normal Force on Box = Weight of Box with books = 134 N
Therefore,
<u>F = 73.7 N = 74 N (rounding off)</u>
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Answer:
1. False
2. True
3. True
Explanation:
1- False —> The relation between electric potential and electric field is given such that
Therefore, for a uniform E field, electric potential is linearly proportional to the distance.
2- True —> The electric field lines always cross the equipotential lines perpendicularly.
3- True —> In order to be a potential difference, one source of electric field is enough. The electric potential will decrease radially according to the following formula:
There is no test charge in the formula, only the source charge. Even when there is no test charge, the potential difference between points in space can exist.
The electrostatic force between two charges q1 and q2 is given by
where
is the Coulomb's constant and r is the distance between the two charges.
If we use F=19.2 N and q1=q2=-3.0 C, we can find the value of r, the distance between the two charges by re-arranging the previous formula:
where
If we use F=19.2 N and q1=q2=-3.0 C, we can find the value of r, the distance between the two charges by re-arranging the previous formula: