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Nadusha1986 [10]
3 years ago
11

PLEASE HELPPP IT DUES IN 30 minutes

Physics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

140m

70sec I cant show my work but I gave you a push

Explanation:

Brainliest?

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A 60 W light bulb has a resistance of 880 Ω
Andreas93 [3]

<h2>\bf{ \underline{Given:- }}</h2>

\sf{• \:  Power \:  (P) = 60 \:  w}

\sf{•  \: Resistance \:  (R) = 880  \: Ω}

\\

<h2>\bf{ \underline{To \:  Find :- }}</h2>

\sf• \:  The  \: Current \:  (I).

\\

\huge\bf{ \underline{ Solution :- }}

\sf We  \: know  \: that,

\bf \red {\bigstar{ \: P = I^{2} R}}

\rightarrow \sf 60 = I^{2}  \times 880

\rightarrow \sf  \frac{60}{880} = I^{2}

\rightarrow \sf  I^{2}   = 0.0681

\rightarrow \sf  I   =  \sqrt{0.0681}

\rightarrow \sf  I   =  0.261 \:  \: (approx.)

\\

\bf The \:   \: value \:  \:  of \:  \:  I  \:  \:   is \:  \:  0.261 \:  \: Amps. \:  \: (approx.)

7 0
3 years ago
A spherical conducting shell has charge Q. A point charge q is placed at the center of the cavity. The charge on the inner surfa
FinnZ [79.3K]

Answer:d

Explanation:

From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.

Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.

and to counter it there is q charge on the surface. So total charge outside the surface is Q+q

7 0
3 years ago
Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled
taurus [48]

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

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3 years ago
Alana organized some resources in a table. which best describes alana’s error? geothermal energy is not found underground. petro
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Which energy is best discribed for you and math
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3 years ago
A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is
Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration a_{c} is given by the following equation:  

a_{c}=\frac{V^{2}}{r} (1)

Where:  

a_{c}=17 m/s^{2} is the <u>centripetal acceleration</u>

V is the<u> tangential speed</u>

r=12 m is the <u>radius</u> of the circle

Isolating V from (1):

V=\sqrt{a_{c}r} (2)

V=\sqrt{(17 m/s^{2})(12 m)}

<u />

Finally:

V=14.28 m/s This is the girl's tangential speed

3 0
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