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Nadusha1986 [10]
3 years ago
11

PLEASE HELPPP IT DUES IN 30 minutes

Physics
1 answer:
Nuetrik [128]3 years ago
6 0

Answer:

140m

70sec I cant show my work but I gave you a push

Explanation:

Brainliest?

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What is primary succession? Give an example.
morpeh [17]

Answer:

primary succession is something that was t there before like a forest it once wasn’t there

Explanation:

7 0
4 years ago
Defiance Drake, Space Adventurer, desperately needs to reach a cargo vessel 100m away, or run out of air and die in deep space.
jolli1 [7]

She misses. She should have accelerated faster in order to get to her target.

5 0
3 years ago
What will be the weight of a box, mass 10Kg on the surface of a hypothetical planet having mass double of Earth and the radius i
vlada-n [284]

Answer:

           W ’= 21.78 kg

Explanation:

The expression for weight is

          W = m g

let's look for the acceleration of gravity with the universal law of gravitation

          F = G m M / r2

          F = m (G M / r2)

without comparing the two equations

          g’= G M / r2

in that case M = 2 Mo and r = 3 ro

where mo and ro are the mass and radius of the earth

         we substitute

         g ’= G 2Mo / (3r₀) 2

         G ’= 2/9 G Mo / r₀²

         g ’= 2/9 g

the weight of the body on this planet is

         W ’= m g’

          W ’= m 2/9 g

let's calculate

          W ’= 2/9 10 9.8

           W ’= 21.78 kg

3 0
3 years ago
A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro
fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

Q=C\times V

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = C_1=2.81 \mu F=2.81\times 10^{-6} F

Charge of first capacitor = Q_1

Voltage across first capacitor = V_1=1220 V

Q_1=C_1V_1

Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C

Capacitance of first capacitor = C_2=6.61\mu F=6.61\times 10^{-6} F

Charge of second capacitor = Q_2

Voltage across first capacitor = V_2=560 V

Q_2=C_2V_2

Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C

Total capacitance in parallel combination:

C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F

Potential across both capacitors = V

V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V

756.88 Volts will be the potential difference across each capacitor.

8 0
3 years ago
What do ocean waves and sound waves have in common?
Virty [35]
Ocean waves and sound waves are : mechanical wave. A and B aren't right at all. and C is  wrong because they aren't electromagnetic.
Mechanical wave is a wave that is an oscillation of matter, and therefore transfers energy through a medium.

Hope this help

4 0
4 years ago
Read 2 more answers
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