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Nadusha1986 [10]

3 years ago

11

PLEASE HELPPP IT DUES IN 30 minutes

1 answer:

Nuetrik [128]3 years ago

6 0

Answer:

140m

70sec I cant show my work but I gave you a push

Explanation:

Brainliest?

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A 60 W light bulb has a resistance of 880 Ω

Andreas93 [3]

<h2> $\bf{ \underline{Given:- }}$ </h2>

$\sf{• \: Power \: (P) = 60 \: w}$

$\sf{• \: Resistance \: (R) = 880 \: Ω}$

$\\$

<h2> $\bf{ \underline{To \: Find :- }}$ </h2>

$\sf• \: The \: Current \: (I).$

$\\$

$\huge\bf{ \underline{ Solution :- }}$

$\sf We \: know \: that,$

$\bf \red {\bigstar{ \: P = I^{2} R}}$

$\rightarrow \sf 60 = I^{2} \times 880$

$\rightarrow \sf \frac{60}{880} = I^{2}$

$\rightarrow \sf I^{2} = 0.0681$

$\rightarrow \sf I = \sqrt{0.0681}$

$\rightarrow \sf I = 0.261 \: \: (approx.)$

$\\$

$\bf The \: \: value \: \: of \: \: I \: \: is \: \: 0.261 \: \: Amps. \: \: (approx.)$

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3 years ago

A spherical conducting shell has charge Q. A point charge q is placed at the center of the cavity. The charge on the inner surfa

FinnZ [79.3K]

Answer:d

Explanation:

From Gauss law Electric field inside a surface is directly proportional to the charge enclosed in it.

Electric field inside a spherical shell is zero and hence there is no charge inside the spherical shell because q charge induces a -q charge on inside surface of spherical shell.

and to counter it there is q charge on the surface. So total charge outside the surface is Q+q

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Ernie speed walks at the rate of 20m/s in 5 seconds. Calculate the distance he traveled

taurus [48]

Answer:

4m

Explanation:

you divide 20m/s by 5 seconds

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Alana organized some resources in a table. which best describes alana’s error? geothermal energy is not found underground. petro

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A girl on a spinning amusements park is 12m from the center of the ride and has a centripetal acceleration of 17 m/s^2. What is

Tanya [424]

Answer: 14.28 m/s

Explanation:

Assuming the girl is spinning with <u>uniform circular motion</u>, her centripetal acceleration $a_{c}$ is given by the following equation:

$a_{c}=\frac{V^{2}}{r}$ (1)

Where:

$a_{c}=17 m/s^{2}$ is the <u>centripetal acceleration</u>

$V$ is the<u> tangential speed</u>

$r=12 m$ is the <u>radius</u> of the circle

Isolating $V$ from (1):

$V=\sqrt{a_{c}r}$ (2)

$V=\sqrt{(17 m/s^{2})(12 m)}$

<u />

Finally:

$V=14.28 m/s$ This is the girl's tangential speed

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3 years ago