3 years ago

The first law of motion applies to what?

1 answer:

3 0

First law of motion- sometimes referred to as the law of inertia. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

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Becky has a younger sister. If the sister was half Becky's age when Becky was 6, and Becky is now 70, how old is Becky's sister?

rjkz [21]

Answer:

Explanation:

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3 years ago

Read 2 more answers

the moon revolves around the earth in a nearly circular orbit kept by gravitational force exerted by the earth work done will be

rodikova [14]

Answer:

Zero because the applied force is perpendicular to the motion of the object.

No work is done on an object moving is a circular path about a central attractive force.

Any work done in such a case would result in a change in the orbit.

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2 years ago

Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?

Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

$KE_1 = \dfrac{1}{2}mv^2$

$2000= \dfrac{1}{2}mv^2$ ........(1)

now, speed of the car is doubled

v' = 2 v

$KE_2 = \dfrac{1}{2}mv'^2$

$KE_2 = \dfrac{1}{2}m(2v)^2$

from equation (1)

$KE_2 = 4\times \dfrac{1}{2}m(v)^2$

$KE_2 = 4\times 2000$

$KE_2 = 8000\ J$

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

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3 years ago

Find the three longest wavelengths (call them λ1, λ2, and λ3) that "fit" on the string, that is, those that satisfy the boundary

zepelin [54]

If you have a string that is fixed on both ends the amplitude of the oscillation must be zero at the beginning and the end of the string. Take a look at the pictures I have attached. It is clear that our fundamental harmonic will have the wavelength of:
$\lambda_1=\frac{L}{2}$
All the higher harmonics are just multiples of the fundamental:
$\lambda_n=n\lambda_1\\ \lambda_n=n\frac{L}{2}$
Three longest wavelengths are:
$n=3; \lambda_3=\frac{3L}{2}\\
n=2; \lambda_2=L\\
n=1; \lambda_=\frac{L}{2}\\
$

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3 years ago

Please help me with these two multiple choice questions!

mafiozo [28]

Answer:

11 is A and 12 is C

Explanation:

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3 years ago