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Feliz [49]
2 years ago
7

The data table shows the cause of unintentional death for various age groups; what can you infer about the 15-24 age group?

Physics
2 answers:
juin [17]2 years ago
8 0

Answer:

A) they are most likely are drivers themselves

Explanation:

taking the test on USAtestprep right now & the other answer on this post was wrong lol

Blizzard [7]2 years ago
3 0

Answer:

D) They most likely died from not wearing a seatbelt.

Explanation:

Their death was caused by a "motor vehicle" (that's what MV stands for in this case). The most logical answer would be D.

You might be interested in
Consider a cylindrical segment of a blood vessel 2.70 cm long and 3.10 mm in diameter. What additional outward force would such
Lyrx [107]

This question is incomplete, the complete question is;

- Calculate the difference in blood pressure between the feet and top of the head of a person who is 1.80m Tall

- Consider a cylindrical segment of a blood vessel 2.70 cm long and 3.10 mm in diameter. What additional outward force would such a vessel need to withstand in the person's feet compared to a similar vessel in her head

Answer:

- the difference in blood pressure is 18698.4 Pa

- the additional outward force F is 4.86 N

Explanation:

Given the data in the question;

we know that the expression for difference in blood pressure is;

ΔP = pgh

where p is density = 1060 kg/m³

g is acceleration due to gravity  = 9.8 m/s²

and h is height = 1.80 m

now we substitute

ΔP = 1060 × 9.8 × 1.80

ΔP = 18698.4 Pa

therefore the difference in blood pressure is 18698.4 Pa

Also given that;

diameter of blood vessel d = 3.10 mm

radius r = 3.10 mm / 2 = 1.55 mm = 0.00155 m

length l = 2.70 cm = 0.027 m

Surface area of the cylindrical segment of a blood vessel is

A = 2πrl

we substitute

A = 2 × π × 0.00155 × 0.027

A = 2.6 × 10⁻⁴ m²

so

the required for will be;

F = PA

we substitute

F = 18698.4 Pa × 2.6 × 10⁻⁴ m²

F = 4.86 N

Therefore, the additional outward force F is 4.86 N

5 0
3 years ago
Brianna pushes a 20 kg box with a force of 50N to achieve an acceleration of 2.5 m/s/s. In order to push a 30 kg box at the same
Elanso [62]

Answer:

She applies 75N of force

Explanation:

F=ma

50=20(2.5)

F=30(2.5)

F=75 N

5 0
2 years ago
A car accelerates uniformly from rest to a speed of 6.6 m/s in 6.5 s. Find the acceleration the car presents during this time?
Art [367]

Answer:

1.02 m/s²

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

Acceleration can simply be defined as the change of velocity with time. Mathematically, it can be expressed as:

a = (v – u) / t

Where:

a is the acceleration.

v is the final velocity.

u is the initial velocity.

t is the time.

With the above formula, we can obtain the acceleration of the car as follow:

Initial velocity (u) = 0 m/s

Final velocity (v) = 6.6 m/s

Time (t) = 6.5 s

Acceleration (a) =.?

a = (v – u) / t

a = (6.6 – 0) / 6.5

a = 6.6 / 6.5

a = 1.02 m/s²

Therefore, the acceleration of the car is 1.02 m/s²

3 0
2 years ago
Do you think that solids can undergo convection? EXPLAIN!
Katarina [22]
 <span>No. Solids can't undergo convection, the reason is that convection works because moving molecules which are hotter and faster have a lower density and therefore rise to the surface. With a solid now, the molecules don't move they can only vibrate.

Therefore solids conduct.</span>
4 0
2 years ago
Read 2 more answers
The hydraulic oil in a car lift has a density of 8.30 102 kg/m³. The weight of the input piston is negligible. The radii of the
denpristay [2]

Answer:

(a) F_i=68.58\ N

(b) F_i=69.903\ N

Explanation:

Given:

  • density of hydraulic oil, \rho=830\ kg.m^{-3}
  • radius of input piston, r_i=6.3\times 10^{-3}\ m
  • radius of output plunger, r_o=0.125\ m
  • force to be supported, F_o=27000\ N

(a)

<u><em>Condition:</em></u><em>The bottom surfaces of piston and plunger at the same level.</em>

According to Pascal's law the pressure of a fluid is exerted equally in all directions against the walls of its container.

Mathematically:

\frac{F_i}{A_i} =\frac{F_o}{A_o}

putting respective values

\frac{F_i}{\pi\times r_i^2} =\frac{27000}{\pi\times r_o^2}

\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2}

F_i=68.58\ N

(b)

<u><em>Condition:</em></u><em>The bottom surface of the output plunger is 1.30 m above that of the input piston.</em>

Given:

h=1.3\ m

Now,

P_i=P_o+\rho.g.h

\frac{F_i}{\pi\times (6.3\times 10^{-3})^2} =\frac{27000}{\pi\times 0.125^2} +830\times 9.8\times 1.3

F_i=69.903\ N

7 0
3 years ago
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