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katen-ka-za [31]
3 years ago
6

Explain Steps. Do not answer. #10 and 11Questions are in the Picture

Mathematics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

Step-by-step explanation:

For problem 10:

1. AE/ED=AC/CB (Since triangle ABC is similar to triangle ADE, we can determine that the ratio of AE to ED is equal to the ratio of AC to CB)

2. AE/ED=(AE+EC)/CB (Rewrite AC as the sum of the lengths forming it; This is sometimes referred to as the Partition Postulate)

3. 9/x=(9+6)/10 (Substitute the given values into this equation)

4. x=6 (Use algebra to solve for x)

For problem 11:

1. AG/AB=AE/AD (Use the same strategy as step one in problem 10, since the rectangles are similar we can create this equation)

2. AG/(AG+GB)=AE/(AE+ED) (Rewrite sides as the some of their parts)

3. 14/(14+7)=18/(18+x) (Substitute given values)

4. x=9 (Solve for x)

lmk if there are mistakes in my explanation, hope this helps :)

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At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

\frac{30}{100}=\frac{1380}{y}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

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There are 4600 students who attend the university.

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Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?
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