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Zigmanuir [339]
4 years ago
15

Two planes, A and B, are flying at the same altitude. If their velocities are vA = 500 km>h and vB = 700 km>h such that th

e angle between their straightline courses is u = 60, determine the velocity of plane B with respect to plane A.
Physics
1 answer:
xenn [34]4 years ago
4 0

Answer:

Velocity of plane B with respect to plane A is 356.21 km

Explanation:

Velocity of plane A v_{A}=500 km/hr

Velocity of plane B v_{B}=700 km/hr

Angle between the their straightline is \theta =60 ^0

velocity of plane B with respect to plane A is given by

V_{BA}= V_{B}sin \theta - V_{A}cos\theta\\V_{BA}= 700 \times sin 60 - 500\times cos60\\V_{BA}=606.21-250\\V_{BA}=356.21 km

Velocity of plane B with respect to plane A is 356.21 km

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What happens when a light ray is parallel to the principal axis ?
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Hope this helps...

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Explain why does the bowling ball decelerate as it travels along the lane
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The main cause of this is Friction. The more oil that is laid down, the less friction there is between the ball and the lane surface. The less friction, the harder it is for the bowler to send the ball in a curved path imparted by the spin that the bowler puts on the ball at the instant of release.

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3 years ago
Three-fourths of the area of a rectangular lawn 30 feet wide by 40 feet long is to be enclosed by a rectangular fence. If the en
satela [25.4K]

Answer:

The fence is 5feet less.

Explanation:

We need to determine

The less amount of fence required, if the enclosure has full width and reduced length, compared to full length and reduced width.

Approach & WorkingArea of lawn = 30 × 403/4th of the area of lawn = ¾(30 × 40) = 30 * 30

 When full width will be fenced, and reduced length will be fenced.

Width = 30 feet30 * L = 30 * 30Hence, length = 30 feetLength of fence needed = 2(30 + 30) = 120 feet

When full length will be fenced, and reduced width will be fenced

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4 0
4 years ago
Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest
mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

Where

\lambda represents wavelength

R represents Rydberg's constant

n_f represents Final energy states

and n_i represents initial energy states

Now Substitute is

1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )

now we will put the values into the above formula

= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )

= 1218888.889 m^{-1}

Now we will rewrite the answer in the term of \lambda

\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m

So, the whole Paschen series is in the part of the spectrum.

8 0
4 years ago
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