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pantera1 [17]
3 years ago
14

Why is a control group important?

Physics
1 answer:
Likurg_2 [28]3 years ago
4 0

Answer:

A. It changes all the time, allowing us to see if the experimental group stays the same.

control group mean the thing the stay the same during the Experiment.

I hope this help

I hope this is correct

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A light beam travels at 1.94×108 in quartz. The wavelength of the light in quartz is 355 .Part AWhat is the index of refraction
Alja [10]

A) 1.55

The speed of light in a medium is given by:

v=\frac{c}{n}

where

c=3\cdot 10^8 m/s is the speed of light in a vacuum

n is the refractive index of the material

In this problem, the speed of light in quartz is

v=1.94\cdot 10^8 m/s

So we can re-arrange the previous formula to find n, the index of refraction of quartz:

n=\frac{c}{v}=\frac{3\cdot 10^8 m/s}{1.94\cdot 10^8 m/s}=1.55

B) 550.3 nm

The relationship between the wavelength of the light in air and in quartz is

\lambda=\frac{\lambda_0}{n}

where

\lambda is the wavelenght in quartz

\lambda_0 is the wavelength in air

n is the refractive index

For the light in this problem, we have

\lambda=355 nm\\n=1.55

Therefore, we can re-arrange the equation to find \lambda_0, the wavelength in air:

\lambda_0 = n\lambda=(1.55)(355 nm)=550.3 nm

4 0
3 years ago
Can you explain hooks law in simple words?
dedylja [7]

Answer:

The extension of a material or a spring is its increase in length when pulled. Hooke’s Law says that the extension of an elastic object is directly proportional to the force applied to it. In other words:

Explanation:

7 0
2 years ago
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Convert 100 Newton into dyne​
Inga [223]

Answer:10000000

Explanation:

5 0
3 years ago
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An avant-garde composer wants to use the Doppler effect in his new opera. As the soprano sings, he wants a large bat to fly towa
Allisa [31]

Answer:

     v’= 9.74 m / s

Explanation:

The Doppler effect is due to the relative movement of the sound source and the receiver of the sound, in this case we must perform the exercise in two steps, the first to find the frequency that the bat hears and then the frequency that the audience hears that also It is sitting.

Frequency shift heard by the murciela, in case the source is still and the observer (bat) moves closer

        f₁ ’= f₀ (v + v₀)/v

         

Frequency shift emitted by the speaker in the bat, in this case the source is moving away from the observer (public sitting) that is at rest

         f₂’= f₁’ v/(v - vs)

           

Note that in this case the bat is observant in one case and emitter in the other, called its velocity v’

            v’= vo = vs

Let's replace

           f₂’= f₀   (v + v’)/v   v/(v -v ’)

           f₂’= f₀   (v + v’) / (v -v ’)

           (v –v’ ) f₂’ / f₀ = v + v ’

           v’ (1+ f₂’ /f₀) = v (f₂’/fo - 1)

           v’ (1 + 1.059) = 340 (1.059 - 1)

           v’= 20.06 / 2.059

           v’= 9.74 m / s

6 0
3 years ago
A wind is blowing a small ice fishing shed along the ice to the east with a 800N force. The shed weighs 2,200N. What would the l
e-lub [12.9K]

Answer:

0.36

Explanation:

The maximum force of friction exerted by the surface is given by:

F_f = \mu N (1)

where

\mu is the coefficient of friction

N is the normal reaction

The shed's weight is 2200 N. Since there is no motion along the vertical direction, the normal reaction is equal and opposite to the weight, so

N = 2200 N

The horizontal force that is pushing the shed is

F = 800 N

In order for it to keep moving, the force of friction (which acts horizontally in the opposite direction) must be not greater than this value. So the maximum force of friction must be

F_f = 800 N

And substituting the values into eq.(1), we can find the maximum value of the coefficient of friction:

\mu = \frac{F_f}{N}=\frac{800}{2200}=0.36

6 0
3 years ago
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