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Tamiku [17]
3 years ago
15

Dhhdhd d jejnen r nejr

Chemistry
2 answers:
Marianna [84]3 years ago
8 0

Answer:

Okay so my wifi is slow. How are you!

Explanation:

I don't see an image so I assume it's free points.....thank you! But if there is an image let me know! and Brainliest?? Pretty please!

aksik [14]3 years ago
6 0

Hey Are u actually looking for help or no?

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What is a meso compound.
Nataly_w [17]

Answer:

A meso compound is a non-optically active member of a set of stereoisomers, at least two of which are optically active.

3 0
2 years ago
What is the percent composition of hydrogen in a compound if the mass of the initial compound is 276 gram and the mass of collec
mariarad [96]

Answer: The percentage composition of hydrogen in the given compound is 15%.

Explanation:

To calculate the percentage composition of hydrogen in a compound, we use the formula:

\%\text{ composition of hydrogen}=\frac{\text{Mass of hydrogen}}{\text{Mass of compound}}\times 100

Where,

Mass of hydrogen = 41.4 grams

Mass of compound = 276 grams

Putting values in above equation, we get:

\%\text{ composition of hydrogen}=\frac{41.4g}{276}{\times 100

Percentage composition of hydrogen in a given compound = 15%

8 0
3 years ago
How are Newton's three laws of motion related
OLga [1]
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
6 0
3 years ago
Read 2 more answers
Calculate the vapor pressure of spherical water droplets of radius (a) 17 nm and (b) 2.0 μm surrounded by water vapor at 298 K.
Montano1993 [528]

Explanation:

Relation between pressure of water and its droplet is as follows.

           ln (\frac{p}{p_{o}}) = \frac{2 \gamma M}{r \rho RT}

where,   p = pressure of droplet

          p_{o} = water pressure in given temperature

          \gamma = 7.99 \times 10^{-3}

           M = Molecular Weight in Kg/Mol (0.018 for water)

            r = radius in meters

     \rho = density of water in Kg/m^{3} (1000 kg/m^{3})

           R = ideal gas constant (8.31)

           T = temperature in Kelvin

(a)   We will calculate the value of p as follows.

           p = e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}

              = e^{\frac{2 \times 0.07199 \times 0.018}{1.7 \times 10^{-8} \times 1000 \times 8.31 \times 298 K} \times 25.2

              = 26.8 torr

(b)  And, vapor pressure of spherical water droplets of radius 2.0 \mu m or 2 \times 10^{-6} m

             p = e^{\frac{2 \gamma M}{r \rho RT}} \times p_{o}

              = e^{\frac{2 \times 0.07199 \times 0.018}{2 \times 10^{-6} \times 1000 \times 8.31 \times 298 K} \times 25.2

              = 25.2 torr

7 0
4 years ago
SnO2 + C → Sn + СО balance​
rewona [7]

Answer:

Tin(IV) Oxide + Carbon = Tin + Carbon Monoxide

Explanation:

7 0
3 years ago
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