The number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.
<h3>How to calculate number of moles?</h3>
The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass. That is;
no. of moles = mass ÷ molar mass
According to this question, a chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. The number of moles can be calculated as follows:
Molar mass of ethanol = 12(2) + 1(5) + 17 = 46g/mol
no of moles = 30g ÷ 46g/mol
no. of moles = 0.65moles
Therefore, the number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.
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(I didn't have this as a question on any of my quizzes, but I will try my best. I wish you luck!)
Answer: Proteins
This is a <u>peptide bond</u>, which is a bond that forms between two <u>amino acids</u> through a condensation reaction. Amino acids make <u>proteins</u>.
Glass 1 Freshwater
The egg went directly to the base of the glass. Consequently it has sunk and did not drift
237.0
237 (1 glass)
1.000
Glass 2
Water with 2 teaspoons of salt
A similar outcome for glass 2 as container 1 when egg was set into the container it sank to the base.
248.4
237
1.048
Glass 3
Water with 3 teaspoons of salt
In reference to glass 1 and 2 the egg sank to the base for a third time.
254.1
237
1.072
Glass 4
Water with 4 teaspoons of salt
The egg remained gliding to where a little bit of the egg was standing out on the top, and when pushed down the egg returned up.
259.8
237
1.096
Hope this helps!
Answer:
It would have 23 chromosomes.
Explanation:
A Diploid is a cell or organism that has paired chromosomes, one from each parent.
In humans, cells other than sex cells, a diploid will have 23 pairs of chromosomes.
Answer:
The law of multiple proportions is the third postulate of Dalton's atomic theory. It states that the masses of one element which combine with a fixed mass of the second element are in a ratio of whole numbers.
Therefore, the masses of oxygen in the two compounds that combine with a fixed mass of carbon should be in a whole number ratio. In 100 grams of the first compound (100 is chosen to make calculations easier), there are 57.1 grams oxygen and 42.9 grams carbon. The mass of oxygen (O) per gram of carbon (C) is:
57.1 g O / 42.9 g C = 1.33 g O per g C
In the 100 grams of the second compound, there are 72.7 grams of oxygen (O) and 27.3 grams of carbon (C). The mass of oxygen per gram of carbon is:
72.7 g O / 27.3 g C = 2.66 g O per g C
Dividing the mass O per g C of the second (larger value) compound:
2.66 / 1.33 = 2
This means that the masses of oxygen that combine with carbon are in a 2:1 ratio. The whole-number ratio is consistent with the law of multiple proportions.
Explanation:
