Answer:
The answer to your question is V2 = 867.3 mL
Explanation:
Data
Volume 1 = V1 = 400 ml
Temperature 1 = T1 = 22°C
Pressure 1 = P1 = 760 mmHg
Volume 2 = V2 = ?
Temperature 2 = T2 = 30°C
Pressure 2 = P2 = 360 mmHg
Process
1.- Convert Celsius to Kelvin
T1 = 22 + 273 = 295°K
T2 = 30 + 273 = 303°K
2.- Use the Combined gas law
P1V1/T1 = P2V2/T2
- Solve for V2
V2 = P1V1T2 / T1P2
- Substitution
V2 = (760 x 400 x 303) / (295 x 360)
- Simplification
V2 = 92112000 / 106200
-Result
V2 = 867.3 mL
<span>when temperature varies:
volume & temperature vary directly @ constant pressure,... Charles' law
pressure & temperature vary directly @ constant volume,... Gay-Lussac's law
when temp is consatnt:
Pressure & volume vary inversely , ...Boyle's law
Hope This Helped! :3</span>
Missing question:
Suppose Gabor, a scuba diver, is at a depth of 15 m. Assume that:
1. The air pressure in his air tract is the same as the net water pressure at this depth. This prevents water from coming in through his nose.
2. The temperature of the air is constant (body temperature).
3. The air acts as an ideal gas.
4. Salt water has an average density of around 1.03 g/cm^3, which translates to an increase in pressure of 1.00 atm for every 10.0 m of depth below the surface. Therefore, for example, at 10.0 m, the net pressure is 2.00 atm.
T = 37°C = 310 K.
p₁ = 2,5 atm = 253,313 kPa.
p₂ = 1 atm = 101,325 kPa.
Ideal gas law: p·V = n·R·T.
n₁ = 253,313 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₁ = 0,589 mol.
n₂ = 101,325 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₂ = 0,2356 mol.
Δn = 0,589 mol - 0,2356 mol = 0,3534 mol.
She has 3 I just did that test. Have a good day
Answer:
Climate is long time intervals and weather is short time intervals
Explanation:
