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3 years ago

Help me..........................

Mathematics

2 answers:

valentinak56 [21]3 years ago

6 0

Answer:

Step-by-step explanation:

There are 5 zeroes in the multiple of ten

svetlana [45]3 years ago

3 0

Answer:

5 zeros

Step-by-step explanation:

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A rectangle has a perimeter of 102 ft and a length of 40 ft. Find the width of the rectangle.

vagabundo [1.1K]

The width is11ft
hope that helps

5 0

3 years ago

Svetach [21]

Answer:

A. b2 – 4ac = 0

Step-by-step explanation:

Hey user☺☺

Option a is correct

Because the graph has only one solution.

As the graph touches the x-axis at one point that means that it will have only one solution for x. But we know that a quadratic equation has two solutions. So the graph will have two equal solution and therefore the discriminant will be 0.

Hope this will help☺☺

5 0

3 years ago

Can someone help me with these please?

saul85 [17]

Point-slope form: y-y1 = m(x-x1)

Standard form: ax + by = c

Slope-intercept form: y = mx+b

Start by finding the slope. We know it is negative since the line is decreasing. The slope is -4/3.

To create point-slope form, we need to get one point from the graph. Let's use (3,0).

$y = -\frac{4}{3}(x-3)$

To create slope-intercept form, we need the slope and the y-intercept. The y-intercept is the point where our equation crosses the y-axis. For this equation, it is 4.

$y = -\frac{4}{3}x + 4$

To get standard form, solve the equation in terms of C.

Point-slope form: y = -4/3(x-3)

Slope-intercept form: y = -4/3x + 4

Standard form: 4/3x + y = 4

7 0

3 years ago

Explain why any of the four operations (+x +) placed between the two terms 5 and-3/(radical sign) 8 will result in an irrational

kompoz [17]

To answer this question we will have to understand the nature of $\sqrt{8}$ .

$\sqrt{8}$ can be rewritten as: $\sqrt{2\times 2\times 2} =2\sqrt{2}$ . Now, $\sqrt{2}$ is an irrational number and thus any of the four operations of addition, multiplication, subtraction or division placed anywhere between any of these terms will always result in an irrational number.