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BaLLatris [955]
3 years ago
6

If 7 - y = 6, then y = A. -29 B. -5 C. 1 D. 29

Mathematics
2 answers:
dimaraw [331]3 years ago
8 0

Answer:

C. 1

Step-by-step explanation:

7 - y = 6

-y +  7 = 6

-y - + 7 - 7 = 6 - 7

-y = -1

(-y=-1)/-1

y = 1

Hope this helps.

Levart [38]3 years ago
8 0

\sf \bf {\boxed {\mathbb {\: C.\:1}}}

\large\mathfrak{{\pmb{\underline{\orange{Step-by-step\:explanation}}{\orange{:}}}}}

7 - y = 6

➺  \: - y =  6 - 7

➺ \:  - y =  - 1

➺ \: y = 1

Therefore the value of y is 1.

\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}

7 - y = 6

➼ \: 7 - 1 = 6

➼ \: 6 = 6

➼ L. H. S. = R. H. S.

Hence verified.

\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♨}}}}}

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3 years ago
Help quick<br><br>subtract a³+b³-3 from the sum of 2a³-3b³+7 and -a³+b³+3ab-a​
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Answer:

-3b³ + 3ab - a + 10

Step-by-step explanation:

2a³ - 3b³ + 7 - a³ + b³ + 3ab - a - (a³+b³-3)

2a³ - 3b³ + 7 - a³ + b³ + 3ab - a - a³ - b³ + 3

-3b³ + 3ab - a + 10

5 0
2 years ago
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For the pair of points find the distance between them and the midpoint of the line segment joining them.(720,50), (125,18)The di
Lana71 [14]

Given two points

(x_1,y_1)

and

(x_2,y_2)

The distance between them is >>>

D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}

The points given are (Sqrt(20), Sqrt(50)) and (Sqrt(125), Sqrt(8)), so their distance is >>>

\begin{gathered} D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ D=\sqrt[]{(\sqrt[]{8}-\sqrt[]{50})^2+(\sqrt[]{125}-\sqrt[]{20})^2} \\ D=\sqrt[]{(\sqrt8)^2-2(\sqrt[]{8})(\sqrt[]{50})+(\sqrt[]{50})^2^{}+(\sqrt[]{125})^2-2(\sqrt[]{125})(\sqrt[]{20})+(\sqrt[]{20})^2} \\ D=\sqrt[]{8-2(2\sqrt[]{2})(5\sqrt[]{2})+50+125-2(5\sqrt[]{5})(2\sqrt[]{5})+20} \\ D=\sqrt[]{8-40+50+125-100+20} \\ D=\sqrt[]{63} \\ D=3\sqrt[]{7} \end{gathered}

----------------------------------------------------------------------------------------------------------

The midpoint formula is >>>

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Plugging in the points, we have >>>

\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ M=(\frac{\sqrt[]{20}+\sqrt[]{125}}{2},\frac{\sqrt[]{50}+\sqrt[]{8}}{2}) \\ M=(\frac{2\sqrt5+5\sqrt[]{5}}{2},\frac{5\sqrt[]{2}+2\sqrt[]{2}}{2}) \\ M=(\frac{7\sqrt[]{5}}{2},\frac{7\sqrt[]{2}}{2}) \end{gathered}

3 0
2 years ago
What is the slope of the line that goes through (-9,-6) and 3,-9)?
Lisa [10]

Answer:

-3/12

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
6w^2 + 11w +8w^2 + 15w -2 and 14w^2 +26w-2 are the equivalent ​
Agata [3.3K]

Answer:

6w^2 + 11w +8w^2 + 15w -2

Get same power near,

6w^2 + 8w^2 + 11<em>w</em>  + 15<em>w</em> -2

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14w^2 +26w-2

Yes equivalent

Step-by-step explanation:

5 0
3 years ago
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