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kenny6666 [7]
3 years ago
7

What would be the balanced chemical equation for the complete combustion of butane ( C4H10 .)

Chemistry
1 answer:
Vilka [71]3 years ago
4 0

The balanced chemical equation b. 2 C₄H₁₀ + 13 O₂ ⇒ 8 CO₂ + 10 H₂O

<h3>Further explanation</h3>

Given

Butane (C₄H₁₀)

Required

Balanced equation

Solution

Formula

Hydrocarbon combustion reactions (specifically alkanes)

\large {\box {\bold {C_nH _ (_2_n _ + _ 2_) + \dfrac {3n + 1} {2} O_2 \rightarrow  nCO_2 + (n + 1) H_2O}}}

In the combustion process, the compound in the reactants is Oxygen (O₂)

If the oxygen needed for combustion is sufficient (or excess) then the combustion results are in the form of CO₂ and H₂O, but if not enough, CO and H₂O will be obtained.

The only answer that contains O₂ in the reactants is option B

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Which is equal to a temperature of 50 degrees F? 18 degrees C, 46 degrees C, 10 degrees C, 32 degrees C?
kakasveta [241]

Answer:

10 degrees C

Explanation:

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3 years ago
Which statements best describe the first stage of cellular respiration
nydimaria [60]

Cellular respiration is the process of taking in glucose (sugar) and converting it into usable energy (ATP) so therefore the first stage would be taking the glucose into your bloodstream.

5 0
4 years ago
An aqueous potassium iodate ( KIO3 ) solution is made by dissolving 562 562 grams of KIO 3 KIO3 in sufficient water so that the
maxonik [38]

Answer:

Molarity of KIO_{3} solution is 0.612 mol/L

Explanation:

Number of moles of a substance = (mass of substance)/(molar mass of the substance)

Molar mass of KIO_{3} = 214 g/mol

So, 562 g of KIO_{3} = \frac{562}{214} moles of KIO_{3} = 2.63 moles of KIO_{3}

Molarity of a solution = (number of moles of solute in solution)/(total volume of solution in liter)

Here solute is KIO_{3} and solvent is water

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So, molarity of KIO_{3} solution = \frac{2.63}{4.30}mol/L = 0.612 mol/L

3 0
3 years ago
by . Figure the density of the liquid in each beaker: The mass and volume of each liquid have been given in Table 1. Using the f
IRINA_888 [86]

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5 0
3 years ago
Using the following information, what are the values of the exponents in the rate expression, rate = k[A]x[B]y
pashok25 [27]

Answer:

The correct option is;

A) x = 2, y = 1

Explanation:

Here we have

k[0.05]^x \cdot [0.05]^y = 0.062 \ M/sec....................(1)

k[0.05]^x \cdot [0.10]^y = 0.123 \ M/sec....................(2)

k[0.100]^x \cdot [0.100]^y = 0.491 \ M/sec  ..............(3)

From experiment (1), (2) it is observed that [A] is held constant and [B] is doubled of which the rate is also observed to be doubled, therefore, when you double a reactant which result in the rate being doubled, the order of the reaction with respect to the reactant is order 1, therefore, y = 1.

Similarly between reaction (2) and (3) when the concentration of the reactant B is doubled and A is held constant the rate of the reaction is multiplied by a factor of 4, therefore, the reaction with respect to that reactant is order 2, therefore, x = 2.

Therefore, the correct option is x = 2, y = 1.

3 0
3 years ago
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