The solution would be like
this for this specific problem:
V^2 = 2AS = 2FS/M
V = sqrt(2FS/M) =
sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps
So the speed of the arrow as it leaves the bow
is 42.5 mps.
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
The answer is:
Both the distance traveled in a given time and the magnitude of the acceleration at a given instant
Hope I Helped!
I think it would be WEIGHT and ROUGHNESS OF SURFACE.
Answer:

Explanation:
To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

Where for definition,

The number of revolution
was given by 20 times, then


We know as well that the salad rotates 6 more times, therefore in angle measurements that is

The cook at the end stop to spin, then using our first equation,

re-arrange to solve
,


We can know find the required time,

Re-arrange to find t, and considering that 



Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of 