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SCORPION-xisa [38]
3 years ago
7

Which statement regarding sound traveling in air is correct?

Physics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer: D. A wave with a shorter wavelength is always faster than one with a longer wavelength

Explanation: "Imagine two sets of waves that have the same speed. <u><em>If one set has a longer wavelength, it will have a lower frequency (more time between waves). If the other set has a shorter wavelength, it will have a higher frequency</em></u> (less time between waves). Light moves even faster AND has shorter wavelengths."

Why it's not C: "The number of complete wavelengths in a given unit of time is called frequency (f). <em><u>As a wavelength increases in size, its frequency and energy (E) decrease</u></em>. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer."

Why it's not B: "The frequency does not change as the sound wave moves from one medium to another. Since the speed changes and the frequency does not, the wavelength must change."

Why it's not A: "Do loud sounds travel faster than soft sounds? No. Both travel at the same speed The speed depends on the medium it passes through. Louder sounds are simply sound waves with higher amplitude traveling at the same speed."

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A block with mass M = 3 kg is moving on a flat surface with constant speed v1 =
Alchen [17]

Answer:

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5 0
2 years ago
A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1
Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) I=0.0085\ A

Explanation:

Given:

  • radius if the coil, r=0.0395\ m
  • no. of turns in the coil, n=520
  • variation of the magnetic field in the coil, B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4
  • resistor connected to the coil, R=560\ \Omega

(a)

we know, according to Faraday's Law:

emf=n.\frac{d\phi}{dt}

where:

d \phi= change in associated magnetic flux

\phi= B.A

where:

A= area enclosed by the coil

Here

A=\pi.r^2

A=\pi\times 0.0395^2

A=0.0049\ m^2

\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049

So, emf:

emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]

emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]

emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]

emf= 0.0306+3.516\times 10^{-4}\ t^3

(b)

Given:

t_0=5.25\ s

Now, emf at given time:

emf=4.7755\times 10^{-2}\ V

∴Current

I=\frac{emf}{R}

I=\frac{4.7755\times 10^{-2}}{560}

I=8.5\times 10^{-5} A

6 0
4 years ago
What force is needed to give a 4.5-kg bowling ball an acceleration of 9 m/s
posledela

Answer:

40.5 N

Explanation:

second law of newto says : F = ma

F= 4.5 × 9 = 40.5 N

3 0
3 years ago
Force has _____. magnitude direction gravity weight
Contact [7]

Answer:

magnitude

Explanation:

7 0
4 years ago
Read 2 more answers
A student plucks a fixed-end string, creating a standing wave with 6.00 nodes (including any nodes at the ends). The string is t
Vesna [10]

1) 2.5 wavelengths

2) 0.208 m

3) 1731 Hz

Explanation:

1)

Standing waves are waves that do not propagate, but instead the particles of the medium just oscillate around a fixed position. Examples of standing waves are the waves produced on a string with fixed ends.

The points of a standing wave in which the amplitude of the oscillation is always zero are called nodes.

The two fixed ends of the string are two nodes. In this problem, we have a total of 6 nodes along the string: this means that there are 4 additional nodes apart from the two ends of the string.

Therefore, this also means that the string oscillate in 5 different segments.

One wavelength is equal to 2 segments of the oscillation: therefore, since here there are 5 segments, this means that the number of wavelengths that we have in this string is

n=\frac{5}{2}=2.5

2)

The wavelength of a wave is the distance between two consecutive crests (or throughs) of the wave.

The wavelength of a standing wave can be also measured as the distance between the nth-node and the (n+2)-th node: so, basically, the wavelength in a standing wave is twice the distance between two nodes:

\lambda = 2 d

where

\lambda is the wavelength

d is the distance between two nodes

Here the length of the string is

L = 0.520 m

And since it oscillates in 5 segments, the  distance between two nodes is

d=\frac{L}{5}=\frac{0.520}{5}=0.104 m

And therefore, the wavelength is

\lambda=2d=2(0.104)=0.208 m

3)

The frequency of a wave is the number of complete oscillations of the wave per second.

The frequency of a wave is related to its speed and wavelength by the wave equation:

v=f\lambda

where

v is the speed

f is the frequency

\lambda is the wavelength

In this problem:

v = 360 m/s is the speed of the wave

\lambda=0.208 m is the wavelength

Therefore, the frequency is

f=\frac{v}{\lambda}=\frac{360}{0.208}=1731 Hz

3 0
3 years ago
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