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SCORPION-xisa [38]
3 years ago
7

Which statement regarding sound traveling in air is correct?

Physics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer: D. A wave with a shorter wavelength is always faster than one with a longer wavelength

Explanation: "Imagine two sets of waves that have the same speed. <u><em>If one set has a longer wavelength, it will have a lower frequency (more time between waves). If the other set has a shorter wavelength, it will have a higher frequency</em></u> (less time between waves). Light moves even faster AND has shorter wavelengths."

Why it's not C: "The number of complete wavelengths in a given unit of time is called frequency (f). <em><u>As a wavelength increases in size, its frequency and energy (E) decrease</u></em>. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer."

Why it's not B: "The frequency does not change as the sound wave moves from one medium to another. Since the speed changes and the frequency does not, the wavelength must change."

Why it's not A: "Do loud sounds travel faster than soft sounds? No. Both travel at the same speed The speed depends on the medium it passes through. Louder sounds are simply sound waves with higher amplitude traveling at the same speed."

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A 87 arrow is fired from a bow whose string exerts an average force of 105 on the arrow over a distance of 75 .
timofeeve [1]

The solution would be like this for this specific problem:

 

V^2 = 2AS = 2FS/M

V = sqrt(2FS/M) = sqrt(2*105*.75/.087) = 44.52817783 = 42.5 mps

So the speed of the arrow as it leaves the bow is 42.5 mps.

I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

6 0
3 years ago
You are doing x-ray diffraction on a crystal that has a cubic structure, using 0.340-nm x rays. Part A If the lattice spacing is
Mrac [35]

Answer:

∅ = 0.26°

Explanation:

Bragg's law states that:

n×λ = 2×d×sin(∅)

<em>where:</em>

  • <em>d is the lattice spacing.</em>
  • <em>λ is the wavelength of the rays.</em>
  • <em>n is the order of the diffracted rays, n = 1.</em>

then:

sin(∅) = λ/2×d

    ∅ = sin^-1(λ/2×d)

    ∅ = 0.26°

6 0
3 years ago
Which of the following quantities can be determined from a speed-time graph of a particle travelling in a straight line?
enot [183]

The answer is:

Both the distance traveled in a given time and the magnitude of the acceleration at a given instant


Hope I Helped!

8 0
3 years ago
Read 2 more answers
Which of the following affect friction (you can choose more than 1)
Anastaziya [24]
I think it would be WEIGHT and ROUGHNESS OF SURFACE.
4 0
3 years ago
Read 2 more answers
Dario, a prep cook at an Italian restaurant, spins a salad spinner and observes that it rotates 20.0 times in 5.00 seconds and t
BabaBlast [244]

Answer:

-\frac{8\pi}{3}rad/s^2

Explanation:

To solve this problem we need to apply the concept related to Angular Acceleration. We can find it through the equation

\omega_f^2-\omega_i^2=2\alpha\theta

Where for definition,

\omega_i = \frac{\theta}{t}

The number of revolution (\theta)was given by 20 times, then

\omega_i = \frac{20*2pi}{5}

\omega = 8\pi rad/s

We know as well that the salad rotates 6 more times, therefore in angle measurements that is

\theta = 6*2\pi rad = 12\pi rad

The cook at the end stop to spin, then using our first equation,

0-8\pi = 2\alpha (12\pi)

re-arrange to solve\alpha ,

\alpha = \frac{-8\pi}{2*12\pi}

\alpha = -\frac{8\pi}{3}rad/s^2

We can know find the required time,

\omega_f-\omega_i = \alpha t

Re-arrange to find t, and considering that \omega_f=0

t= \frac{\omega_i}{\alpha}

t=\frac{-8\pi}{-8\pi/3}

t=3s

Therefore take for the salad spinner to come to rest is 3 seconds with acceleration of -\frac{8\pi}{3}rad/s^2

6 0
3 years ago
Read 2 more answers
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