3 years ago

CAN YOU EXPLAIN?

Physics

1 answer:

Anni [7]3 years ago

4 0

<h2>Answer:</h2><h2><u>this</u><u> this is an image of this is helpful to you please thank you</u></h2>

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A car is traveling at vx = 30 m/s . The driver applies the brakes and the car decelerates at ax = -5.0 m/s2 . What is the stoppi

____ [38]

Answer:

90 m

Explanation:

We use an ecuation of uniformly accelerated motion, which allows us to find the distance traveled by the car from the moment that driver applies the brakes until it stops completely, that is, when its final speed is zero.

$v_{f}^2=v_{o}^2+2ad$

We isolate the variable d, knowing that the final speed $v_{f}$ is zero

$d=\frac{-v_{o}^2}{2a}\\d=\frac{-(30m/s)^2}{2(-5m/s^2)}=90 m$

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3 years ago

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Blizzard [7]

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Identify the type of chemical reaction:<br><br> CaCO3 -->CaO + CO2

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Explanation:

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2 years ago

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Trucks 1 and 2 are traveling at the same constant velocity but truck 1's energy due to motion is two times less than that of tru

brilliants [131]

Kinetic energy = 0.5 * m * v²

m mass
v velocity

If the velocity stays the same and the kinetic energy goes down by a factor of 2, the mass must go down by a factor of 2 also.

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3 years ago

A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0°-angle with the horizontal.

crimeas [40]

Answer:

Explanation:

Given:

length of ladder $r_L = 14m$

weight of ladder $F_L = 490N$

position of firefighter $r_F = 3.8m$

weight of firefighter $F_F = 820N$

angle of ladder $\alpha = 63$

Unknown:

force of the wall on the ladder $F_W$

force of friction on base of ladder $F_R$

normal force on base of ladder $F_N$

From the free body diagram of the sketch you get 3 equations:

$F_x = ma_x = F_W - F_R = 0\\ F_y = ma_y = F_N - F_F - F_L = 0\\ \tau _P = \overrightarrow{r} \times \overrightarrow{F} = r_FF_Fcos\alpha + \frac{1}{2}r_LF_Lcos\alpha - r_LF_Wsin\alpha = 0$