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Gekata [30.6K]
3 years ago
8

How does the frequency of gamma rays compare to the frequency of microwaves?

Physics
1 answer:
vekshin13 years ago
4 0

Answer:

Frequency of gamma rays is more than microwave.                

Explanation:

The number of vibrations per unit time is called frequency of a wave. The SI unit of frequency is Hertz. It is equal to s^{-1}.

The frequency of gamma rays is of the order of 10^{20}\ Hz. The frequency of microwave is of the order of 10^8\ Hz.

It is clear that gamma rays have more frequency that of the microwave.

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Why does an empty plate not heat up in the microwave?
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Because the plate doesn't have water, and it's water which is heated by the microwave
7 0
3 years ago
This equation goes with which law?
Alchen [17]

Answer:

I think that's Newton's second law of motion

Explanation:

f = m(v-u)

________

t

since a = (v-u)t

f = ma

3 0
3 years ago
a tire has a tread pattern with a crevice every 4.00 cm. each crevice makes a single vibration as the tire moves. what is the fr
koban [17]

the frequency (in hz) of these vibrations if the car moves at 24.2 m/s is 605 HZ .

Calculation :

frequency = \frac{number of contacts}{second}

frequency = \frac{24.2 m/s}{1}*100cm*\frac{1}{4cm}

= 605 HZ

Frequency describes the number of waves passing through a particular location in a particular time. So if the wave takes 1/2 second to travel, the frequency is 2 per second. If it takes 1/100th of an hour, the frequency is 100 per hour.

Frequency is the number of occurrences of a repeating event per unit time. ... sometimes called time-frequency for clarity,

Learn more about frequency here : brainly.com/question/254161

#SPJ4

5 0
1 year ago
The term 'DENSITY' tells us…
pogonyaev

Answer:

The answer is A

Explanation:

Density basically shows the amount of mass per volume of something. You can easily find Density with the equation D=m/v

D= Density

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3 0
3 years ago
A uniform plank 8.00 m in length with mass 50.0 kg is supported at two points located 1.00 m and 5.00 m, respectively, from the
andreev551 [17]

To solve the problem it is necessary to use Newton's second law and statistical equilibrium equations.

According to Newton's second law we have to

F = mg

where,

m= mass

g = gravitational acceleration

For the balance to break, there must be a mass M located at the right end.

We will define the mass m as the mass of the body, located in an equidistant center of the corners equal to 4m.

In this way, applying the static equilibrium equations, we have to sum up torques at point B,

\sum \tau = 0

Regarding the forces we have,

3Mg-1mg=0

Re-arrange to find M,

M = \frac{m}{3}

M = \frac{50}{3}

M = 16.67Kg

Therefore the maximum additional mass you could place on the right hand end of the plank and have the plank still be at rest is 16.67Kg

8 0
3 years ago
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