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Mademuasel [1]
2 years ago
12

(2)Answer asappppp pls I neee help

Chemistry
1 answer:
pav-90 [236]2 years ago
4 0

Answer:

It’s correct

Explanation:

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When copper (Cu) and oxygen (O) combine, two different compounds are formed. The first compound contains 88.8% copper by mass, a
marusya05 [52]
1) Chemical reaction 1: 4Cu + O₂ →  2Cu₂O.
n(Cu) = 88,8 ÷ 63,55.
n(Cu) = 1,4.
n(O) = 11,2 ÷ 16.
n(O) = 0,7.
n(Cu) : n(O) = 1,4 : 0,7.
n(Cu) : n(O) = 2 : 1.
Compound is Cu₂O.
2) Chemical reaction 2: 2Cu + O₂ →  2CuO.
n(Cu) = 79,9 ÷ 63,55.
n(Cu) = 1,257.
n(O) = 20,1 ÷ 16.
n(O) = 1,257.
n(Cu) : n(O) = 1,257 : 1,257.
n(Cu) : n(O) = 1 : 1.
Compound is CuO.
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3 years ago
Which reaction should be used to convert propene into an alkyl halide?
skelet666 [1.2K]
Substitution that is it 
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Which of the following is not a characteristic of reliable science?
natta225 [31]

Answer:

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4 0
3 years ago
The atomic number of gold (Au) is 79, and it has a mass number of 197. How many electrons are present in each atom of gold?
aliya0001 [1]
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8 0
3 years ago
1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is
earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

\frac{V_{1} }{T_{1} }= \frac{V_{2} }{T_{2} }

So in this case, V1 = 6 L and T1 = 80° C. Similarly, T2 = 40° C. So we have to determine the V2.

\frac{6}{80}=\frac{V_{2} }{40}

V_{2}=\frac{6*40}{80}=3 L

So, 3 L will be the final volume for the gas as per Charle's law.

4 0
3 years ago
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