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ahrayia [7]
3 years ago
9

Write an equation for the reaction of the Tollens reagent withheptanal?

Chemistry
1 answer:
dangina [55]3 years ago
8 0

Answer:

CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+  3 H_2 O = CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3

Explanation:

Tollens test is carried out to perceive difference between aldehydes and ketones on the basis of their capability to oxidized easily.

when Tollens react with aldehyde (heptanal) , a silver mirror is form on inner side of container.

The reaction between tollens and heptanal is given as

CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 CHO + 2[Ag(NH_3)_2]+ 3 H_2 O = CH_3 CH_2 CH_2 CH_2 CH_2 CH_2 COOH +2Ag + 4NH_3

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Compound name for C3F8
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Answer:

Perflutren

Explanation:

Perflutren is a fluorinated hydrocarbon and gaseous substance used as an imaging contrast agent.

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An element or compound which occurs naturally in the earth is a ___?
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An element or compound which occurs naturally in the earth is a mineral
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4.The other light bulb will stay on and glow brightly.
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What kind of bond is created by a week electrical attraction between polar molecules
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8 0
3 years ago
Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.76
aliina [53]

The given question is incomplete, the complete question is:

Lead forms two compounds with oxygen. One contains 2.98g of lead and 0.461g of oxygen. The other contains 9.89g of lead and 0.763g of oxygen. For a given mass of oxygen, what is the lowest whole-number mass ratio of lead in the two compounds that combines with a given mass of oxygen?

Answer:

The lowest whole-number mass ratio in the two compounds is 1:2.

Explanation:

There is a need to find the mole ratio between lead and oxygen atoms in order to find the whole-number mass ratio of lead in the two compounds. In the first compound, the given mass of lead is 2.98 grams, the molar mass of lead is 207.2 gram per mole.  

The no. of moles can be determined by using the formula,  

moles = mass/molecular mass

moles = 2.98 g/207.2 g/mol

= 0.0144 moles

The mass of oxygen in the compound I is 0.461 grams, the molecular mass of oxygen is 16 gram per mol.  

moles = 0.461 g /16 g/mol

= 0.0288 moles

The ratio between the lead and oxygen in the compound I is 0.0144/0.0288 = 1:2

On the other hand, in the compound II, the mass of lead given is 9.89 grams, therefore, the moles of lead in compound II is,  

moles = 9.89 g / 207.2 g/mol

= 0.0477 moles

The mass of oxygen given in compound II is 0.763 grams, the moles of oxygen present in the compound II is,  

moles = 0.763 g / 16 g

= 0.0477 moles

The ratio between the lead and oxygen in the compound II is, 0.0477 moles lead /0.0477 moles oxygen = 1:1

Hence, of the two compounds, the lowest ratio is found in the compound I, that is, 1:2.  

4 0
3 years ago
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