Question

The amount of energy required to heat 0.5 kilograms of water until the temperature increases 12° C is about

Answer 1

Answer:

Q = 25104 / 4.184 = 6000 Calories or 6 Kcal

Explanation

Energy can be calculated by the equation

Q = m x Cp x delta T

where

m = mass = 0.5 kg

Cp = specific heat of water = 4184 J

Delta T = 12 degrees

Multiplying all

Q = 0.5 x 4184 x 12 = 25104 Joules

Converting it to Calories

Q = 25104 / 4.184 = 6000 Calories or 6 Kcal