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3 years ago

Find f(3) if f(x)=2x+4

Mathematics

1 answer:

solong [7]3 years ago

3 0

Answer:

f(3) = 10

Step-by-step explanation:

If x = 3 then fill in the x's on the original equation and solve;

f(x) = 2x + 4

f(3) = 2(3) + 4

2 x 3 = 6

6 + 4 = 10

So, f(3) = 10

Hope this helps!!!

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Suppose that a particle following the given path c(t) flies off on a tangent at t = t0. Compute the position of the particle at

Svetach [21]

Answer:

(30,35,0)

Step-by-step explanation:

We are given that

$C(t)=(2t^2,t^3-4t,0)$

$t_0=3,t_1=4$

The velocity of particle, $v(t)=c'(t)=(4t,3t^2-4,0)$

Substitute $t_0=3$

$C(3)=(2(3)^2,(3)^3-4(3),0))=(18,15,0)$

$v(3)=(4(3),3(3)^2-4,0)=(12,23,0)$

The tangent line at t=3 is given by

$l(t)=c(2)+(t-3)v(3)=(18,15,0)+(t-3)(12,23,0)$

Now, substitute t=4

$l(4)=(18,15,0)+(4-3)+(12,23,0)=(18,12,0)+(12,23,0)$

$l(4)=(30,35,0)$

Hence, the position of particle at $t_1=4$ =(30,35,0)

4 0

3 years ago

If the graph of the function h defined by h(x)=-3x^2+3 is translated vertically upward by 3 units , it becomes the graph of a fu

Slav-nsk [51]

G(x) = h(x) +3 . . . . . h translated upward by 3 units

g(x) = (-3x² +3) +3
g(x) = -3x² +6 . . . . . . . . . the desired expression for g(x)

6 0

3 years ago

Which value of b would make x²+bx-30 factorable? A. -31 B. -17 C. 11 D. 13

dimulka [17.4K]

Answer:

D. 13

Step-by-step explanation:

well since it's a quadratic equation, it can be written in the form of ax²+bx+c=0. So we have a=1, b=b and c= -30. Also the roots are given by the equation-

x= -b± $\sqrt{b^{2}-4ac}$ /2a. So all I did was put the number from the choices which would satisfy the sqrt part and that turned out to be 13 since $\sqrt{13^{2}-4*1*(-30)$ = $\sqrt{289}$ = 17. So b=13.