For what values of h does the equation have real solutions.
√(3x-h)= x+3
1 answer:
Square both side to get
3x-h = (x+3)^2
distribute the squared
3x - h = x^2 + 6x + 9
subtract 3x from both sides
-h = x^2 + 3x + 9
The answer will only have real solutions if the right side is factorable
h= -19, and 2.25 are both values that would make the right side factorable
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