2 years ago

For what values of h does the equation have real solutions. √(3x-h)= x+3

Mathematics

1 answer:

Andru [333]2 years ago

4 0

Square both side to get

3x-h = (x+3)^2

distribute the squared

3x - h = x^2 + 6x + 9

subtract 3x from both sides

-h = x^2 + 3x + 9

The answer will only have real solutions if the right side is factorable

h= -19, and 2.25 are both values that would make the right side factorable

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