Kinetic energy = (1/2) (mass) (speed)²
Since the 'speed' in the KE formula is squared, if the car's speed
increases by 5 times, its kinetic energy increases by (5²) = 25 times.
The loss of kinetic energy in a skid is just the wo0rk done by friction
between the tires and pavement. So the skid distance is proportional
to the initial kinetic energy, and the car must skid 25 times as far when
it enters the skid at the higher speed.
25 x 30m = 750 meters
<h2>
Answer:</h2>
<em>1.33 x 10⁻ ⁴ T outwards.</em>
<em></em>
<h2>
Explanation:</h2>
The equation for the magnetic force (F) on a wire whose length is L and carrying a current I in a magnetic field (B) that is uniform is given by;
F = ILB sin θ ---------------------(i)
Where;
θ = angle between the direction of the current and that of the magnetic field.
From the question,
F = 4.0 × 10⁻² N
I = 12A
L = 25m
θ = 90°
<em>Substitute these values into equation(i) and solve as follows;</em>
4.0 × 10⁻² = 12 x 25 x B x sin 90°
4.0 × 10⁻² = 300 x B x 1
4.0 × 10⁻² = 300B
0.04 = 300B
B = 
B = 0.000133
B = 1.33 x 10⁻ ⁴ T
To get the direction of the magnetic field, the right-hand rule is used.
If the right hand fingers are positioned in the correct order specified by the right hand rule, then it would be seen that the magnetic field is directed outwards.
Therefore, the magnitude and direction of the magnetic field at this location is <em>1.33 x 10⁻ ⁴ T outwards.</em>
I’m not sure what you are asking
Answer:
Induced emf through a loop of wire is 3.5 V.
Explanation:
It is given that,
Initial magnetic flux, 
Final magnetic flux, 
The magnetic flux through a loop of wire decreases in a time of 0.4 s, t = 0.4 s
We need to find the average value of the induced emf. It is equivalent to the rate of change of magnetic flux i.e.



So, the value of the induced emf through a loop of wire is 3.5 V.
I believe the correct answer is C good luck!