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Valentin [98]
3 years ago
8

A butterfly flies from the top of a tree in the center of a garden to rest on top of a red flower at the garden's edge. The tree

is 9.0 m taller than the flower, and the garden is 17 m wide.
Determine the magnitude of the butterfly's displacement.

Express your answer using two significant figures.

Physics
2 answers:
denpristay [2]3 years ago
4 0

Answer:

R=12 m

Explanation:

I have drawn a vector form which I attached here.Please first go through that

Given Data

y (Tree Taller) = 9.0 m

x(Distance from center to edge is)= 8.5 m

To find

R(magnitude of the butterfly's displacement

)

Solution

R=\sqrt{x^{2} +y^{2} }\\R=\sqrt{9^{2}+8.5^{2}  }\\ R=12.379m

Convert to two significant figures

R=12 m

Zielflug [23.3K]3 years ago
3 0

The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.

x=\sqrt{(9)^2+(0.17)^2}

x = 9.0061 \approx 9.0 m

Therefore the magnitude of the butterfly's displacement is 9m

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Oxygen gas (mass: 16 grams)

Products:

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Answer: 8.8 m

Explanation:

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In this case, because the Initial Velocity of the ball is a vecotr, it can be defined using its two directionals compounds. One, on the Y-axis and another on the X-axis. This can be related, on how a hypotenuse is the product of two legs of the triangle. Because of this, each one of this, can be know using the following equation:

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Now the movement is divided on two parts, one under the effect of gravity and another one with a constant velocity.

To know how tall does the baseball hit the wall, we need to know first how much time it takes the ball to reach the wall on the X-axis. The wall is 17.5m away, we velocity on Vx that is constant we can calculate as it follow:

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Know with the time, we can calculate the how tall it got on that time with the following equation:

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x = (Vy*T) + (\frac{1}{2} *g*T^{2} )

x = ((9.62m/s)*0.68s) + (\frac{1}{2} *(9.81m/s^{2})*(0.68s)^{2} )

x = 8.8 m

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