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Ilya [14]
3 years ago
15

30 points! to who helps me out

Physics
1 answer:
olga_2 [115]3 years ago
6 0
The three forces are:
Push force from dog = 20 N (sideways)
Weight of cart = 98 N (downwards)
Normal force = 98 N (upwards)
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On a rectangle with length 100 m, width 50m and 2 vehicles stationed together. Find the time that they meet given that car A tra
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Answer:

T=35.625sec

Explanation:

From the question we are told that:

Length L=100 m

Width W=50m

Velocity of Car A V_A=5m/s

Velocity of Car B V_B=3m/s

Distance traveled by car A before car B moves

d_l=5*3

d_l=15

Therefore total distance traveled at same time interval

D=total\ distance-d_l

Where

Total distance=Perimeter of rectangle

P=2(L+B)

P=2(100+50)

P=300

Therefore

D=total\ distance-d_l

D=300-15\\D=285m

Generally the equation for time taken to meet is mathematically given by

T=\frac{Distance D}{Relative\ speed V_r}

Where

Relative speed = Speed of car A +Speed of car B

V_r=V_A+V_B

V_r=5+3

V_r=8m/s

Therefore the time taken to meet

T=\frac{ D}{ V_r}

T=\frac{ 285}{ 8}

T=35.625sec

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