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ohaa [14]
3 years ago
7

If using the method of completing the square to solve the quadratic equation

Mathematics
1 answer:
Softa [21]3 years ago
6 0

Answer:

The number that would be added to make x^2-19x-3=0 a complete square is \mathbf{(\frac{19}{2})^2}

Step-by-step explanation:

We need to solve the expression x^2-19x-3=0 using completing the square method.

Completing square method is of form: (a-b)^2=a^2-2ab+b^2

We need to find the term, that it a complete square

The middle term is -19x so, it can be made as: -2(x)(19/2) according to the formula a^2-2ab+b^2

We have a=x and b=19/2

So, adding and subtracting (19/2)^2

x^2-2(x)(\frac{19}{2} )+(\frac{19}{2})^2- (\frac{19}{2})^2-3=0\\(x-\frac{19}{2})^2-\frac{361}{4}-3=0\\

So, the number that would be added to make x^2-19x-3=0 a complete square is \mathbf{(\frac{19}{2})^2}

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Let Mary Sue have m necklaces and Betty have b necklaces.

And they have 603 necklaces altogether, that is

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4 years ago
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asambeis [7]

Answer:

<h2>The circumference is multipled by 4.</h2>

Step-by-step explanation:

The formula of an area of a circle"

A=\pi r^2

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C=2\pi r

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The radius has increased fourfold, therefore:

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Calculate the radius:

\pi r^2=2152.96\pi             <em>divide both sides by π</em>

r^2=2152.96\to r=\sqrt{2152.96}\\\\r=46.4\ in

Calculate the circumference of both circles:

r=11.6\ in\\\\C=2\pi(11.6)=23.2\pi\ in

r=46.4\ in\\\\C'=2\pi(46.4)=92.8\pi\ in

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