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cupoosta [38]
2 years ago
12

Is x+y=8; (2,4) a solution or an equation

Mathematics
2 answers:
Yakvenalex [24]2 years ago
4 0
No if you plug in the numbers for the variables 2+4≠8
Sever21 [200]2 years ago
3 0

Answer: neither

Step-by-step explanation: if you plug in 2 and 4 for x and y it does not equal 8

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Jeremy is buying a new bicycle. For the style he likes best, the bicycle shop sells 26-inch and 29-inch frames in blue, red, and
Leno4ka [110]

Answer:

1 out of 6

Step-by-step explanation:

there are 6 different combinations

26in - blue

26in- red

26in- black

29in - blue

29in - red

29in - black

The probability then come out to 1 out of 6

8 0
2 years ago
Please help due soon!!!
butalik [34]

Hey there!


Question #1.
2^6 + (2^3)^3

= 64 + (8)^3

= 64 + 8^3

= 64 + 512

= 576


Therefore, the answer should be:

Option A. 576


Question #2.
11^-4 * 11^8

= 1/14,641 * 214,358,881

= 14,641

≈ 11^4

Therefore, the answer should be:

Option C. 11^4


Good luck on your assignment & enjoy your day!


~Amphitrite1040:)

3 0
2 years ago
Read 2 more answers
N is a positive integer.Explain why n(n-1) must be an even number.
V125BC [204]

Answer:

n and (n - 1) are consecutive integers.

Step-by-step explanation:

We are given 'n', a positive integer.

This 'n' can either be odd or even.

Case I:

When 'n' is odd

The n - 1 is even.

Note that the product of odd and even is always even. That is the product of n and (n - 1) is even.

Case II:

when 'n' is even

Then n - 1 is odd.

Again, using the similar logic we can say that the product of n and n - 1 should be even because here, 'n - 1' is even and 'n' is odd.

4 0
3 years ago
The length of a rectangle is 1 ft less than double the width, and the area of the rectangle is 21 ft^2. Find the dimensions of t
ICE Princess25 [194]

Let the width be w, then length = 2w - 1

Area = length times width = w(2w - 1) = 21.

Thus, 2w^2 - w = 21 or 2w^2 - w - 21 = 0

Solving the quadratic equation gives that w = 3.5.

Therefore, width is 3.5 ft and length is 2(3.5) - 1 = 6 ft.

4 0
3 years ago
Which equation is equivalent to √x^2+81 = x+10
jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2

By definition:(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2

x ^ 2 + 81 = x ^ 2 + 2 (x) (10) + (10) ^ 2\\x ^ 2 + 81 = x ^ 2 + 20x +100

Thus, x ^ 2 + 81 = x ^ 2 + 20x +100 is equivalent to \sqrt {x ^ 2 + 81} = x + 10

Answer:

x ^ 2 + 81 = x ^ 2 + 20x +100

Option D

4 0
3 years ago
Read 2 more answers
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