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3 years ago

Is x+y=8; (2,4) a solution or an equation

Mathematics

2 answers:

Yakvenalex [24]3 years ago

4 0

No if you plug in the numbers for the variables 2+4≠8

Sever21 [200]3 years ago

3 0

Answer: neither

Step-by-step explanation: if you plug in 2 and 4 for x and y it does not equal 8

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Which equation can be used to calculate the area of the shaded triangle in the figure below?

Lilit [14]

C 1 over 2 (16 x 6) = 48 square feet.
hope this helps!

6 0

3 years ago

For the functions h and g, which statement is true if h(x) = x and g(x) = (x + 14)?

pickupchik [31]

Answer:

For the functions h and g, which statement is true if h(x) = x and g(x) = (x + 14)?

(F) The graph of g is the result of the graph of h being translated right 14 units.

(G) The graph of g is the result of the graph of h being translated left 14 units.

(H) The graph of g is steeper than the graph of h.

(J) The graph of g is less steep than the graph of h.

Step-by-step explanation:

For the functions h and g, which statement is true if h(x) = x and g(x) = (x + 14)?

(F) The graph of g is the result of the graph of h being translated right 14 units.

(G) The graph of g is the result of the graph of h being translated left 14 units.

(H) The graph of g is steeper than the graph of h.

(J) The graph of g is less steep than the graph of h.

8 0

3 years ago

X6-6x3 5=0 solucion por favor

PSYCHO15rus [73]

I hope this helps you

4 0

4 years ago

A one-parameter family of solutions of the DE P' = P( 1 - P) is given below. P = c1et/1 + c1et Does any solution curve pass thro

topjm [15]

Answer:

a. The curve $P(t) = -\frac{6e^t}{5-6e^t}$ passes through the point (0, 6)

b. No solution of the curve $P(t)$ passes through the point (0, 1)

Step-by-step explanation:

Consider the family of the solution of DE $P' = P(1 - P)$ is $P = \frac{c_1e^t}{1 + c_1e^t}$

a. If any solution passes through the point (0, 6), then there is $c_1$ such that the point (0, 6) satisfies the solution $P = \frac{c_1e^t}{1 + c_1e^t}$

Substitute $t = 0, P = 6$ in $P = \frac{c_1e^t}{1 + c_1e^t}$ and then solve the equation to obtain $c_1$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\P(0) = \frac{c_1e^0}{1+c_1e^0}\\ 6 = \frac{c_1}{1 + c_1}\\ c_1 = -\frac{6}{5}$

Therefore, the curve $P(t) = -\frac{6e^t}{5 - 6e^t}$ passes through the point (0, 6)

b. If any solution passes through the point(0, 1), then there is $c_1$ such that the point (0, 1) satisfies the solution $P = \frac{c_1e^t}{1+c_1e^t}$

$P(t) = \frac{c_1e^t}{1 + c_1e^t}\\ P(0) = \frac{c_1e^0}{1 + c_1e^0}\\ 1 = \frac{c_1}{1+c_1} \\1 + c_1 = c_1$

this is not possible

Hence, there is no curve $P(t)$ that exists which passes through the point (0, 1)

4 0

3 years ago

7) Using the Distributive Property (think of the double rainbows!), write an equivalent expression to 11(7 - 3). Your answer sho

Volgvan

Answer:

77-33

Step-by-step explanation:

Distributive Property → a(b-c)=ab-ac

11(7-3) = 77-33

8 0

3 years ago