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2 years ago

HELP!!! please marked brainliest

Mathematics

1 answer:

Arisa [49]2 years ago

6 0

Answer:

m∠KLM = 100

Step-by-step explanation:

First, make both equal to each other

26x + 22 = 38x - 14

Subtract 26x from both sides

22 = 12x - 14

Add 14 to both sides to isolate the variable

32 = 12x

Divide both sides by 12

x = 3

----------------- To find m∠KLM take one angle:

38x - 14

Replace the x with 3

38(3) - 14

Multiply 38 by 3

114 - 14

Subtract 14 from 114

100

m∠KLM = 100

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Answer:

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Step-by-step explanation:

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3 years ago

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Help me out , plzzzzz!!

natta225 [31]

Answer:

a. 5,040 ways

b. 210 ways

Step-by-step explanation:

a) We want to pick 4 numbers out of 10 given that orders matter

If orders do matter, it will be a permutation problem

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n P r = n!/(n-r)!

In this case, n is 10 and r is 4

Thus, we have it that;

10 P 4 = 10!/(10-4)! = 5,040

b) if orders do not matter

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2 years ago

Writing Algebraic Expressions the product of 3 and X

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Step-by-step explanation:

$3 \times x$

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2 years ago

Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

this is the perimeter of triangle ABC

6 0

3 years ago