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Vesna [10]
3 years ago
12

X=-4a^2+3ab+12b^2 Y=9a^2+ab-7b^2 Y+X=Need HELP NOW PLEASE​

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0
Step 1. (((0-(4•(a2)))+3ab)+(12•(b2)))+(((9•(a2))+ab)-7b2)
step 2. (((0-(4•(a2)))+3ab)+(12•(b2)))+((32a2+ab)-7b2)
step 3.(((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)
step 4. (((0-(4•(a2)))+3ab)+(22•3b2))+(9a2+ab-7b2)
step 5. 5.1 Factoring 5a2 + 4ab + 5b2
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Please help me I need to get a good grade on this
Julli [10]
1 4/5 - 2/5 = r you minus the total she has already walked or ran from the total she plans on running to get “r”
8 0
3 years ago
Find the 7th term of the geometric sequence whose common ratio is 1/3 and whose first term is 5.
wolverine [178]

Answer:

t_7 =\frac{5}{729}

Step-by-step explanation:

We are given that:

First term (a) = 5

common ratio (r) =\frac{1}{3}

The nth term of a geometric sequence is given as:

t_n =ar^{n-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{7-1} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \bigg(\frac{1}{3}\bigg) ^{6} \\\therefore t_7 =5\times \frac{1}{729}\\\\\huge\red{\boxed{\therefore t_7 =\frac{5}{729} }}

8 0
3 years ago
The box which measures 70cm X 36cm X 12cm is to be covered by a canvas. How many meters of canvas of width 80cm would be require
grigory [225]

Answer:

142.2 meters.  

Step-by-step explanation:

We have been given that a box measures 70 cm X 36 cm X 12 cm is to be covered by a canvas.      

Let us find total surface area of box using surface area formula of cuboid.

\text{Total surface area of cuboid}=2(lb+bh+hl), where,

l = Length of cuboid,

b = Breadth of cuboid,

w = Width of cuboid.

\text{Total surface area of box}=2(70\cdot36+36\cdot 12+12\cdot 70)

\text{Total surface area of box}=2(2520+432+840)

\text{Total surface area of box}=2(3792)

\text{Total surface area of box}=7584

Therefore, the total surface area of box will be 7584 square cm.  

To find the length of canvas that will cover 150 boxes, we will divide total surface area of 150 such boxes by width of canvass as total surface area of canvas will also be the same.

\text{Width of canvas* Length of canvass}=\text{Total surface area of 150 boxes}

80\text{ cm}\times\text{ Length of canvass}=150\times 7584\text{cm}^2

\text{ Length of canvass}=\frac{150\times 7584\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=\frac{1137600\text{ cm}^2}{80\text{ cm}}

\text{ Length of canvass}=14220\text{ cm}

Let us convert the length of canvas into meters by dividing 14220 by 100 as 1 meter equals to 100 cm.

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100\frac{cm}{m}}

\text{ Length of canvass}=\frac{14220\text{ cm}}{100}\times\frac{m}{cm}

\text{ Length of canvass}=142.20\text{ m}

Therefore, 142.2 meters of canvas of width 80 cm required to cover 150 such boxes.

5 0
3 years ago
A carton has a length of 2 2/3 feet, width of 1 1/3 feet, and a height of 1 1/2. What is the volume of the carton? A( 4 cubic fe
notsponge [240]

Answer:

The volume of the carton is 5 1/3 cubic feet

Step-by-step explanation:

A carton has a length of 2 2/3 feet, width of 1 1/3 feet, and a height of 1 1/2.

The dimensions can be rewritten as

Length of carton =2 2/3 = 8/3 converting to improper fraction).

width of 1 1/3 feet = 4/3 feet

and a height of 1 1/2= 3/2 ,feet

volume of the carton = length of the carton × width of the carton × height of the carton

Volume of carton = 8/3 ×4/3 × 3/2

= 96/18 cubic feet

Converting to mixed fractions, we have

96/18= 5 1/3 cubic feet

8 0
3 years ago
What the rule for the transformation is<br>​
AleksandrR [38]
Answer: (x + 3, y - 4)

Explanation: The shape in the middle goes to the right three and down four to match the shape at the bottom
8 0
3 years ago
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