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jarptica [38.1K]
3 years ago
11

Be + S electron transfermation

Chemistry
1 answer:
weeeeeb [17]3 years ago
3 0

Explanation:

plzz mark me brainliest

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Evaluate the carbon dioxide molecule. Explain how to determine if double or triple bonds exist in the molecule.
S_A_V [24]

Answer:

It contain double Bond.

Explanation:

To determine weather the bond is double or triple simply check the electron involved in mutual sharing of an electron if 2 electron takes parts it said to be double or if 3 it said to be triple.

4 0
3 years ago
NEED HELP ASAP!!!!!!!!!!!!!!!!!!!!!!
Paraphin [41]
<h2>Answer:  C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

<h3>                       ∴  1s²2s²2p⁶ is the noble gas (neon)</h3>

7 0
3 years ago
Using logarithms, you determined the A)Solubility B)Temperatures C)ph
dem82 [27]

Answer:

the answer is pH

Explanation:

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7 0
4 years ago
Decide if the following definite article and noun agreement is CORRECT or INCORRECT <br> La mapa
GREYUIT [131]
It's el mapa so the answer is incorrect. Even though mapa has an 'a' at the end, you will still use el.
8 0
4 years ago
Read 2 more answers
How would you prepare 1.00 L of a 0.50 M solution of each of the following?
Lunna [17]

Answer:

Take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water.

Explanation:

Hello,

In this case, for the dilution process from concentrated  12-M hydrochloric acid to 1.00 L of the diluted 0.50M hydrochloric acid, the volume of concentrated HCl you must take is computed by considering that the moles remain constant for all dilution processes as shown below:

n_1=n_2

Which can also be written in terms of concentrations and volumes:

M_1V_1=M_2V_2

Thus, solving for the initial volume or aliquot that must be taken from the 12-M HCl, we obtain:

V_1=\frac{M_2V_2}{M_1} \\\\V_1=\frac{1.00L*0.5M}{12M}\\ \\V_1=0.0417L=41.7mL

It means that you must take approx 41.7 mL of 12-M HCl in a 1.00-L flask and fill the rest of the volume with distilled water for such preparation.

Best regards.

6 0
4 years ago
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