Mass of ammonia produced : 121.38 g
<h3>Further explanation</h3>
Given
Reaction
3H₂(g) + N₂(g) ⇒ 2NH₃(g)
100g of N₂
Required
Ammonia produced
Solution
mol of N₂ :
From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :
mass of NH₃(MW=17 g/mol) :
The average atomic mass of the imaginary element : 47.255 amu
<h3>Further explanation </h3>
The elements in nature have several types of isotopes
Isotopes are elements that have the same Atomic Number (Proton)
Atomic mass is the average atomic mass of all its isotopes
Mass atom X = mass isotope 1 . % + mass isotope 2.% ..
isotope E-47 47.011 amu, 87.34%
isotope E-48 48.008 amu, 6.895
isotope E-49 50.009 amu, 5.77%
The average atomic mass :
Answer:
The correct option is False
Explanation:
Ionization energy is the <em>minimum amount of energy required to remove a valence electron from one mole of an atom in it's gaseous state</em>. Ionization energy requires the removal of an electron from a gaseous atom. The definition in the question is that of electronegativity.
Electronegativity is the <u>ability of an atom to attract electrons towards itself in a chemical bond.</u>
Answer:
The volume of reactant measured at STP left over is 409.9 L
Explanation:
To determine the masses of each component, we need to know the concentration first in terms of molality which is mol per mass of solution. Assuming the density of the solution is equal to that of water we would find:
molality = 0.160 mol KBr / L ( 1 L / 1 kg solution ) = 0.160 mol KBr / kg solution
mass KBr = 0.160 mol KBr / kg solution (.0750 kg solution ) ( 119 g KBr / mol KBr ) = 1.428 g KBr
mass solvent = 75 - 1.428 = 73.572 g water
