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Nitella [24]
3 years ago
12

Compound 1 has a composition of 46.7 mass % of element A and 53.3 mass % of element B. A and B also form a second binary compoun

d (compound 2). If the compositions of the two compounds are consistent with the law of multiple proportions, which of the following compositions could be that of compound 2?
Chemistry
1 answer:
Leviafan [203]3 years ago
5 0

A summary of the Law of multiple proportions is that if A and B form more than one compound, and B1 is the amount of element B which reacts with a fixed mass of A in compound 1, and B2 is the amount of B which reacts with the same fixed mass of B to form compound 2, then the ratio B1:B2 will be small whole numbers.

This law is rather simplistic, and given the range of compounds known today the definition of 'small' is now rather large... but, to answer the question:

in compound one 1.14133g of B reacts with 1g of A. (1.14133=53.3/46.7)  

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8 0
2 years ago
What am I supposed to do using the Science Textbook? Please help!!!!!!!<br>See the picture above.
baherus [9]
It looks like part of the Periodic Table. Do you have to write down the most common Periodic Table elements? If so, then that's probably what you should do.
6 0
2 years ago
Why is productivity greatest near the ocean’s surface
Kobotan [32]

Answer:

Sunlight penetrates the top layers of the ocean, so photosynthesis occurs there.

Explanation:

5 0
2 years ago
(10 points) A student gathers the following data for the freezing point depression of a pure solvent and solvent-solute solution
Alex17521 [72]

Answer:

548 g/mol

Explanation:

The freezing point depression of a solvent occurs when a nonvolatile solute is added to it. Because of the interactions between solute-solvent, it is more difficult to break the bonds, so the phase change will need more energy, and the freezing point will drop, which is called cryoscopy.

The drop in temperature can be calculated by:

ΔT = Kf*W*i

Where Kf is the cryoscopy constant of the solvent, W is the molality, and i is the van't Hoff factor, which indicates the fraction of the solute that dissolves.

The molality represents how much moles (n) of the solute is presented in each kg of the solvent (m2), thus

W = n/m2

The number of moles is the mass of the solute (m1) in g, divided by the molar mass (M1) of it:

W = m1/(M1*m2)

So, by the data:

0.2214 = 0.632/(M1*0.00521)

0.00115M1 = 0.632

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6 0
3 years ago
Read 2 more answers
What is the oxidation state of S in so ??​
Marina86 [1]

Answer:

+2

Explanation:

If a compound SO existed, we would identify the oxidation state of sulfur using the following logic:

  • oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
  • oxygen typically has an oxidation state of -2;
  • we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
  • if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
  • write the equation for the net charge of 0 by adding all individual charges of the two atoms: x + (-2) = 0;
  • hence, x = 2.

That said, in this hypothetical compound S would have an oxidation state of +2.

6 0
3 years ago
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