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Amanda [17]
3 years ago
11

FIRST TO ANSWER GET BRAINLIEST What is the mass in grams of 3.04 mol of ammonia vapor, NH3?

Chemistry
1 answer:
Irina18 [472]3 years ago
5 0

Answer:

3.04 mol NH3* (17.03 g NH3/ 1 mol NH3)= 51.8 g NH3~

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A balloon is floating around outside your window. The temperature outside is 21 ∘C , and the air pressure is 0.700 atm . Your ne
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V=162L

Explanation:

Hello,

In this case, we can compute the required volume by using the ideal gas equation as shown below:

PV=nRT

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Which property describes the way substances react with other substances to form new substances?
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Chemical Property describes the way substances react with other substances to form new substances.

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3 years ago
Read 2 more answers
How many reactant molecules and product gas molecules are in this equation?
Mice21 [21]

Answer:

N₂  = 6.022 × 10²³ molecules

H₂ = 18.066 × 10²³ molecules

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Explanation:

Chemical equation;

N₂ + 3H₂     →  2NH₃

It can be seen that there are one mole of nitrogen three mole of hydrogen and two moles of ammonia are present in this equation. The number of molecules of reactant and product would be calculated by using Avogadro number.

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

Number of molecules of nitrogen gas:

1 mol = 6.022 × 10²³ molecules

Number of molecules of hydrogen:

3 mol × 6.022 × 10²³ molecules/ 1 mol

18.066 × 10²³ molecules

Number of molecules of ammonia:

2 mol × 6.022 × 10²³ molecules/ 1 mol

12.044 × 10²³ molecules

6 0
4 years ago
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