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pochemuha
3 years ago
14

a fixed amount of gas at 25.0 degrees Celsius occupies a volume of 10.0 L when the pressure is 629 torr. Use Charles law to calc

ulate the volume the gas will occupy when the temperature is increased to 105 degrees Celsius while maintaining the pressure at 629 torr?
Chemistry
1 answer:
kirill [66]3 years ago
8 0

Explanation:

Since pressure remained constant, we can eliminate P from the equation

\frac{pv }{t}  =  \frac{pv}{t}

Doing some algebra and converting temperature to Kevin by adding 273, you should obtain the same result.

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svetlana [45]
I will assume that the sign ? between the C and the CCH3 is a triple bond, and I will represent it by three vertical lines |||


So the reaction is:


<span>CH3CH2CH2CH2C ||| CCH3+2Br2 ---->


This is a typical reaction known as halogenation of alkines.


This is an addition reaction, i.e. the alkyne undergoes an addition of the Br2 (and it also happens with Cl2) to the triple bond to form a tetra halide.


.
                                                                                                      Br   Br
</span>                                                                                                        |     |
<span><span>CH3CH2CH2CH2C ||| CCH3+2Br2 ---->  CH3 CH2 CH2 CH2 C - C</span> - CH3
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3 0
3 years ago
Please Help me
dangina [55]
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6 0
3 years ago
? Answer the question below. Type your response in the space provided. What volume of a 2.5 M stock solution of acetic acid (HC2
Novay_Z [31]
Data: 
M_{concentrated} = 2.5\:mol
V_{concentrated} = ?
M_{dilute} = 0.50\:mol
V_{dilute} = 100\:mL\to0.100\:L
<span>
Formula: Dilution Calculations

</span>M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
<span>
Solving:

</span>
M_{concentrated} * V_{concentrated} = M_{dilute} * V_{dilute}
2.5 * V_{concentrated} = 0.50 * 0.100
2.5V_{concentrated} = 0.05
V_{concentrated} =  \frac{0.05}{2.5}
\boxed{\boxed{V_{concentrated} = 0.02\:L\:or\:20\:mL}} \end{array}}\qquad\quad\checkmark<span>







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3 0
4 years ago
The half-life of radon gas is approximately four days. Four weeks after the introduction of radon into a sealed room, the fracti
maksim [4K]

The fraction of the original amount remaining is closest to 1/128

<h3>Determination of the number of half-lives</h3>
  • Half-life (t½) = 4 days
  • Time (t) = 4 weeks = 4 × 7 = 28 days
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n = t / t½

n = 28 / 4

n = 7

<h3>How to determine the amount remaining </h3>
  • Original amount (N₀) = 100 g
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N = N₀ / 2ⁿ

N = 100 / 2⁷

N = 0.78125 g

<h3>How to determine the fraction remaining </h3>
  • Original amount (N₀) = 100 g
  • Amount remaining (N)= 0.78125 g
  • Fraction remaining =?

Fraction remaining = N / N₀

Fraction remaining = 0.78125 / 100

Fraction remaining = 1/128

Learn more about half life:

brainly.com/question/26374513

7 0
2 years ago
What is chemical change? what are some ways to tell chemical change happened?
andrew-mc [135]

Answer:

A chemical change occurs when the reactants chemical compositions have changed

Explanation:

a change in colour, change in temperature, change in smell, formation of a precipitate, or the formation of gas bubbles

Hopes this helps

4 0
2 years ago
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