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The time that it takes the computer to receive acknowledgment for a packet is 0.1667 seconds. The time it takes to send out a packet is 4 x 10⁻³seconds
<h3>1 The acknowledgment time for the packet</h3>
speed = 2.4x108m/s
Distance = 40000 km,
Time = distance/ speed
= 40000 x10³/ 2.4x10⁸m/s
= 0.1667
The time that it take is 0.1667 seconds.
b. Number of bytes = 5000
5000x 8 = 40000bits
10 mbps = 10000 kbps
10000 kbps = 10000000
packet size / bit rate = 40000/10000000
= 4 x 10⁻³seconds to send a packet out
Read more on computer bandwith here: brainly.com/question/27020560
Answer:
cp command
Explanation:
When copying files and directories under a Linux operating systems, we usually make use of the cp command . In Linux, this cp command is the one that is entered in a shell to copy a file from one location to another, and also possibly on another different file system.
Answer:
- import java.util.Scanner;
- public class Main {
-
- public static void main(String[] args) {
- Scanner input = new Scanner(System.in);
- System.out.print("Enter meal total: $");
- double meal = input.nextDouble();
- double finalAmount = meal + meal *0.09;
-
- if(finalAmount * 0.15 > 8){
- finalAmount = finalAmount + 8;
- }else{
- finalAmount = finalAmount + finalAmount * 0.15;
- }
- System.out.println("Final amount: $" + finalAmount);
- }
- }
Explanation:
Firstly, create a Scanner object and print user to input total meal (Line 5-7). Next, add the 9% tax to the meal total (Line 8). Use an if statement to check if the finalAmount multiplied by the 15% of tips is bigger than 8 (Line 10), if so, only add 8 to the final amount (Line 11). If not, add 15% tips to final amount (Line 12). At last, print out the final amount (Line 15).
