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3 years ago

Lengths of Rectangles

Mathematics

1 answer:

Furkat [3]3 years ago

6 0

Answer:

AB = 5

BC = 12

AC = 13

Step-by-step explanation:

A rectangle is a quadrilateral and therefore, opposite sides are parallel and congruent to each other. Thus:

AB = CD = 12

AB = 12

BC = AD = 5

BC = 5

AC is a diagonal of the rectangle, use Pythagorean theorem to find it's length as follows:

AC² = AD² + CD²

Plug in the values

AC² = 5² + 12²

AC² = 169

AC = √169

AC = 13

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kramer

Answer:

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Step-by-step explanation:

for scientific notation, all you need to do is start at the decimal point (or end of whole number) and move over the amount of spaces (the exponent) to the right. if it is a negative exponent, instead of moving to the right, you should move to the left.

for example : 500 x 10^3

when you start from the last zero and move to the right, you need to fill the space with three zeroes.

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4 years ago

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NeTakaya

Answer: $P\left ( A\right )=0.45$

$P\left ( B\right )=0.32$

Step-by-step explanation:

Given

$P\left ( A\cup B\right )=0.626$

$P\left ( A\cap B\right )=0.144$

and we know

$P\left ( A\cup B\right )=P\left ( A\right )+P\left ( B\right )-P\left ( A\cap B\right )$

$0.626=P\left ( A\right )+P\left ( B\right )-0.144$

$0.77=P\left ( A\right )+P\left ( B\right )$ -------1

as it is given

A and B are independent therefore

$P\left ( A\cap B\right )=P\left ( A\right )\cdot P\left ( B\right )$

$0.144=P\left ( A\right )\cdot P\left ( B\right )$

Substitute value of $P\left ( B\right )$ in 1

$0.77=P\left ( A\right )+\frac{0.144}{P\left ( A\right )}$

on solving $P\left ( A\right )=0.45$

$P\left ( B\right )=0.32$

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For the polynomial function ƒ(x) = x4 − 16x2, find the zeros. Then determine the multiplicity at each zero and state whether the

ddd [48]

Our function f(x) can be rewritten if we factor out a common x^2 from each term:
$f(x) = x^2(x^2-16)$
Now inside the parentheses we have a polynomial of the form a^2 - b^2, or the difference of two perfect squares, which can be factored as (a+b)(a-b) so we have:
$f(x)=x^2(x-4)(x+4)$
Setting our function equal to zero gives us the roots x = 0, x = 4, and x = -4.
The multiplicity of the root zero is two since it occurs twice, and the others are one since they occur only once. If you graph the function you can see that it will only touch the x-axis at x = 0, but will cross the x-axis at x = 4 and x = -4.

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4 years ago

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Fofino [41]

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Step-by-step explanation:

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3 years ago

A square and a rectangle have the same perimeter. The square has a side length of 8x units. The rectangle has a length of (10x+8

Elden [556K]

Well we know that the perimeters are equal so:
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we know perimeter for square is the 4 sides of same lengths added up or 4*s

the perimeter of a rectangle is the then4 sides with 2 being equal added up so 2*L + 2*W

we know that a square side equAls s and it says that s=8x. So:
Psqu = 4 * (8x) (substitute 8x for s)

we know that the rectangle L =10x + 8 and W =10. So
Prect = 2 *(10x + 8) + 2 * (10)

we know :
Prect = Psqu so:
4 * (8x) =2 *(10x + 8) + 2 * (10)
32x = 20x + 16 + 20
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So if x equals 3 we can sub x in for square perimeter
Psqu = 4 *(8 * 3)
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we can check this with rectangle perimeter
P = 2 *(10 * 3 + 8) + 2 *10
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P = 96

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4 years ago