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2 years ago

Find the radius of a circe given the area 25pi square inch.

Mathematics

1 answer:

Elis [28]2 years ago

6 0

Answer:

Radius = 5 inches

Step-by-step explanation:

1) We have to use the equation for the area of a circle to find the radius of the circle.

Area of a circle = πr^2

2) Plug in the information we already know, i.e., the area.

25π = πr^2

3) Cancel out the π on each side.

25 = r^2

4) Take the square root of 25

r = $\sqrt{25\\}$

r = 5

5) The radius is 5 inches.

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Multiply 2^(9)*2^(2)*2^(4)

Flauer [41]

Answer:

2 ^ 15

Step-by-step explanation:

2 ^9 * 2 ^ 2 * 2 ^ 4

When we multiply numbers with the same base, we can add the exponents

a^ b * a^ c = a^(b+c)

2 ^9 * 2 ^ 2 * 2 ^ 4

2 ^ ( 9+2+4)

2 ^ 15

3 0

2 years ago

Read 2 more answers

If an 8-foot ladder is leaned against a wall with its foot braced 4 feet from the wall's base, how far up the wall will the top

vivado [14]

We know that
see the picture to better understand the problem
in the right triangle ABC
Applying the Pythagoras Theorem
AB²=BC²+AC²-------> BC²=AB²-AC²
AB=8 ft
AC=4 ft
BC²=8²-4²-----> BC²=48--------> BC=√48-------> BC=6.93 ft

the answer is
6.93 ft

8 0

2 years ago

What can this simplify to?

Mkey [24]

→ Chapter : Exponentiation ←
≡ We know that:
⇔ $\frac{a^{x}}{a^{y}}=a^{(x-y)}$
⇔ $\frac{1}{a^{-b}}=a^{b}$

≡ Solution:
⇒ $\frac{4^{2}g^{3}p^{-2}}{4^{5}g^{12}m^{-5}}$
⇒ $[4^{(2-5)}].[g^{(3-12)}].[p^{-2}].[m^{5}]$
⇒ $[4^{-3}].[g^{-9}].[p^{-2}].[m^{5}]$
∴ $\boxed{\frac{1}{64}g^{-9}p^{-2}m^{5}}$ or $\boxed{\frac{m^{5}}{64g^{9}p^{2}}}$

7 0

3 years ago

Jason is traveling by car from his home to his office. He has gone 3.5 miles so far. From this point on, he can cover 100 miles

Nutka1998 [239]

There is step to step calculation

Hope is helpful