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nika2105 [10]
3 years ago
11

i need help with this question on my homework, i never learned it and i want to know the answer and how to do it. can someone he

lp? (26 points)

Mathematics
1 answer:
nydimaria [60]3 years ago
8 0

The heavy line means  the values on this part are in the solution set. . The open circle means that this value ( - 3) is NOT included in the solution set.

So the answer is  x > -3.

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Suppose a manufacturer finds that 95% of their production is normal but the final 5% has one or more flaws. Each flawed good has
RUDIKE [14]

Answer:

1)    

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW        0.01             0.95

2) 0.04 and $0.04

3) 0.025 and $0.025

4) 0.015 and $0.015

5) 0.95 and $0.95

Step-by-step explanation:

Given that;

financial cost = $1

p(flaw) = 0.05  

p(type 1 flaw / flaw) = 80% = 0.8

p(type 2 flaw / flaw) = 50% = 0.5

p( type 1 and 2 flaw/flaw) = 30% = 0.30

1) Bivariate Table

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

p( only 1 flow) = 0.04 - 0.015 = 0.025

p( only 2 flow) =  0.025 - 0.015 = 0.01

THEREFORE  the Bivariate Table;

FLAW                         TYPE2         NO TYPE2 FLAW

TYPE1                         0.015           0.025

NO TYPE1 FLAW       0.01              0.95

2) probability and expectations of type 1 flaw?

p( type 1 flaw) = p(flaw) × p(type 1 flaw/flaw) = 0.05 × 0.8 = 0.04

Expected financial cost to the firm per good = $1 × 0.04 = $0.04

3)  probability and expectation of Type 2 flaw

p( type 2 flaw) = p(flaw) × p(type 2 flaw/flaw)  = 0.05 × 0.5 = 0.025

Expected financial cost to the firm per good = $1 × 0.025 = $0.025

4) probability and expectations of Type 1 and 2 flaws

p( type 1 and 2 flaw) =  p(flow) × p( type 1 & 2 flaw/flaw) = 0.05 × 0.3 = 0.015

Expected financial cost to the firm per good = $1 * 0.015 = $0.015

5) probability and expectations of no flaws?

Probability of no flaw = P(No flaw) =95% =  0.95

Expected financial cost saved the firm per good due to no flaw

= $1 × 0.95 = $0.95

5 0
3 years ago
the city of brice is planning to build a skate park. An architect designed the area shown at the right. in the plan, the perimet
Amiraneli [1.4K]

The actual skate park's perimeter is 130 inches.

Explanation:

Step 1; Assume the initial garden has a width of y inches. It is given that the length is 25 inches. The perimeter of any given rectangle is twice the sum of the length and the width of the same rectangle. The initial perimeter is given as 80 inches.

Perimeter = 2 × (length of the rectange + width of the rectangle).

80 = 2 × (25 + y), 40 = 25 + y, y = 40 - 25 = 15

So the initial park has a width of 15 inches.

Step 2; Now we calculate the actual skate park's perimeter. The length is given as 50 inches and the width was found to be 15 inches.

Perimeter = 2 × (length of the rectange + width of the rectangle).

Perimeter = 2 × (50 + 15) = 2 × 65 = 130 inches.

5 0
3 years ago
Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
Masteriza [31]

Answer:

  • See below

Step-by-step explanation:

<u>Given equation:</u>

  • x² + y² + 8x - 4y - 7 = 0

<u>Convert this to standard form by completing the square:</u>

  • (x - h)² + (y - k)² = r², where (h, k) - center, r - radius
  • x² + 2*4x + 4² + y² - 2*2y + 2² - 16 - 4 - 7 = 0
  • (x + 4)² + (y - 2)² - 27 = 0
  • (x + 4)² + (y - 2)² = 27
  • (x + 4)² + (y - 2)² = (√27)²

The center is (- 4, 2) and the radius is √27

3 0
2 years ago
In order to earn a grade of C in the midterm, a student must have a score that is within 6 points of the average score of 62 poi
Elena L [17]

Answer:

Step-by-step explanation:

70%

5 0
3 years ago
I need the assistance of smarter beings than I..... I'm so lost.....
alukav5142 [94]

Answer:

\sf \bold{ 1 * (-3)^{n-1}}

Explanation:

first term, a₁ = 1

difference between the terms: -3

  • used geometric formula : \bold{\sf  a_1 * (r)^{n-1}}

<u>where "a₁ is first term" and "r refers to common difference"</u>

  • formula for this nth term: \sf \bold{ 1 * (-3)^{n-1}}
4 0
2 years ago
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