Side lengths of the squares are x and y
4x+4y=52
divide both sides by 4 for simlicity
x+y=13
area is 89 so
x²+y²=89
ok
so
x+y=13
minus x both sides
y=13-x
sub that for y in other equation
x²+y²=89
x²+(13-x)²=89
x²+x²-26x+169=89
2x²-26x+169=89
minus 89 both sides
2x²-26x+80=0
undistribute 2
2(x²-13x+40)=0
factor
2(x-8)(x-5)=0
set to zero
x-8=0
x=8
x-5=0
x=5
x=5 or 8
find y
y=13-x
13-8=5
13-5=8
each square has side length of 5 or 8
perimiter is 4 times the area around so
5*4=20
8*4=32
the perimiters are 20cm and 32cm
Answer:
Option C.
Step-by-step explanation:
The given absolute value inequality is
Isolate the absolute value by subtracting 5 from both sides.
Therefore, the correct option is C.
We can further solve this, to find the solution of the given inequality.
Subtract 12 from each sides.
The solution of given inequality is .
B=-3.18 I hope that helps
<h3>Part 1</h3>
If we simplify, both Joe and Hope factored the polynomial correctly but Joe didn't complete it fully.
<u>The first binomial can be further factored:</u>
<h3>Part 2</h3>
The quadratic expression needs to have two roots in order to be factored as two binomials.
<u>The discriminant must be positive or zero:</u>
We have a = 3, b = k, c = -8
<u>So we get following inequality:</u>
- k² - 4*3*(-8) ≥ 0
- k² + 96 ≥ 0
<u>Since k² is positive for any value of k, the solution is any value of k:</u>
